names_and_dob = [] #empty list to hold user input
num_employee = int(input("Number of employees : ")) #determines the number of employees
print("First name, last name, D.O.B.(Hit ENTER after each input):")
for employee in range(0, num_employee): #creates arrays for each given employee
user_given = [input(), input(), input()]
names_and_dob.append(user_given) #adds each individual variable to an array through .append
def get_date(names_and_dob):
dob = []
for date in names_and_dob:
dob.append(date[2])
return dob
print(names_and_dob)
import datetime
birthdate = "/".join(get_date(names_and_dob))
month,day,year = map(int, birthdate.split("/"))
today = datetime.date.today()
age = today.year - year - ((today.month, today.day) < (month, day))
print(age)``` I'm currently working on this code for class and the current problem I'm facing is when I try to calculate for age in the most recent text, my code can only handle the input for one date (ValueError: too many values to unpack (expected 3)). I know the issue lies within the variable birthdate but I'm unsure of the proper way to set it up? Because before I tried adding "/".join it wouldnt work because it was a list of strings.#🔒 ValueError: too many values to unpack
warm nest
fast flumeBOT
```py
names_and_dob = [] #empty list to hold user input
num_employee = int(input...
@warm nest
Python help channel opened
stuck galleon
```py
names_and_dob = [] #empty list to hold user input
num_employee = int(input...
The birthdate = line doesn't seem to make any sense.
What are you intending get_date to do?
warm nest
my code asks for a first name, last, and date of birth, get_date separates the date given from the other input so I can use it to calculate age from that date
I know it doesnt make sense lol, but I messaged my TA about it days ago a few times and he hasnt got back to me😭
stuck galleon
```py
names_and_dob = [] #empty list to hold user input
num_employee = int(input...
In this code, the length of the list returned by get_date is directly tied to the value of num_employee. That line I mentioned doesn't make sense because you're taking the date of birth of each employee, and putting them all into a list. You're then trying to treat that list of dates of birth as a day, month, and year. What exact day, month, and year are you day,month,year line?
Or, in other words, you're trying to use a list of employee birthdates to get a single birthdate. Did you mean to calculate a birthdate for each employee?
warm nest
Yes that is what I meant to do, I understand that " ".join puts them all into one list but before when I tried just birthdate = (get_date(names_and_dob)), there is no attribute to split in the list
noble hemlock
Yes that is what I meant to do, I understand that " ".join puts them all into on...
.join() returns a string, which is the concatenation of the strings in the iterable. It doesn't put it into a list.
!e
items = ["A", "B", "C"]
print(type(", ".join(items)))
@noble hemlock :white_check_mark: Your 3.12 eval job has completed with return code 0.
<class 'str'>
apologies, i havent been coding for long so I slip up on termanolgy but i appreciate the correction
noble hemlock
user_given = [input(), input(), input()] is creating a list.
names_and_dob.append(user_given) is appending that list to another list. #adds each individual variable to an array through .append It's not adding each variable, like you think it is.
!e
dob_list = []
user_given = ["john", "doe", "01/01/91"]
dob_list.append(user_given)
print(dob_list)
@noble hemlock :white_check_mark: Your 3.12 eval job has completed with return code 0.
[['john', 'doe', '01/01/91']]
So now you have a nested list.
user_given = [input(), input(), input()] This part would be a nightmare if you had to put in... let's say 20 users. You would have to do 3 inputs per user, multiply that by 20 users...
You can do something a little simpler
user_data = input("Enter first name, last name, dob seperated by a space: ").split(" ")
# example input 'John Doe 01/01/21'
but where you're having the issue at...
This is what is in birthdate
john doe 1/1/1
jane doe 2/2/2
[['john', 'doe', '1/1/1'], ['jane', 'doe', '2/2/2']]
1/1/1/2/2/2 # contents of birthdate
birthdate = "/".join(get_date(names_and_dob)) combines all the dob's in the list, into one string.
So, you're trying to unack 3 values... from 6 that are there.
Which increases the more users you have.
john doe 1/1/1
jane doe 2/2/2
bob smith 3/3/3
[['john', 'doe', '1/1/1'], ['jane', 'doe', '2/2/2'], ['bob', 'smith', '3/3/3']]
1/1/1/2/2/2/3/3/3 # contents of birthdate
I understand that is where my issue is and what it is, I'm just unsure of how to fix it
noble hemlock
So, names_and_dob is a list that contains a list of people and their information.
Each item in that list has list object that has a first name, last name, and dob.
one second...
!e
people = [["john", "doe", "1/1/1"], ["jane", "doe", "2/2/2"], ["bob", "smith", "3/3/3"]]
for fname, lname, dob in people:
print(fname, lname, dob)
@noble hemlock :white_check_mark: Your 3.12 eval job has completed with return code 0.
001 | john doe 1/1/1
002 | jane doe 2/2/2
003 | bob smith 3/3/3
i do not understand how this relates to my original issue?
noble hemlock
Sorry, juggling this and cooking. Okay, so now you have the dob.
!e
people = [["john", "doe", "01/01/1986"], ["jane", "doe", "02/20/2000"], ["bob", "smith", "03/30/2013"]]
for fname, lname, dob in people:
month, day, year = dob.split("/")
print(month, day, year)
@noble hemlock :white_check_mark: Your 3.12 eval job has completed with return code 0.
001 | 01 01 1986
002 | 02 20 2000
003 | 03 30 2013
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