How does this work?
#🔒 Define function
arctic arrow
arctic arrow
def numbers(num="Please input an number :) "):
print(num)
x = int(input("Enter a digit: "))
y = int(input("Enter another digit: "))
print(divide(x))
print(divide(y))
def divide(n):
return n // n
numbers()
I'm only receiving the output 1.0
rapid frost
```py
def numbers(num="Please input an number :) "):
print(num)
x = int(...
In the divide function, you are taking a number n, and dividing it by itself. Any number divided by itself is always 1
brave oar
You're only passing one argument to the function.
arctic arrow
I need another argument?
brave oar
!res
cinder gateBOT
brave oar
There are some great resources there.
brave oar
Well right now you are only passing one value at a time to the function. So since your function executes return n // n then divide(3) will return the result of 3 // 3
and so on for any number you call it with
If you want to specify different values for the numerator and denominator you need to pass the function two separate values. The way you tell Python that you want to do this is by defining the function to take two arguments.
arctic arrow
I see
brave oar
!e ```py
def divide(x: int, y: int) -> int:
return x // y
print(divide(10, 5))
@brave oar :white_check_mark: Your 3.12 eval job has completed with return code 0.
2
ahh I see
so if I change it to
def divide(x: int, y: int) -> int:
return x // y
print(divide(6, 2))
It would change x and y to 6 and 2 then
brave oar
you got it
arctic arrow
So I have to call divide instead?
brave oar
Instead of what?
arctic arrow
numbers
brave oar
No, your numbers function is doing something different.
arctic arrow
TypeError: divide() missing 1 required positional argument: 'y'
It gives me this error
I don't understand why
brave oar
show your code
arctic arrow
so if I change it to
```py
def divide(x: int, y: int) -> int:
return x // y
...
doesn't this function essentially have 2 arguments?
def numbers(num="Please input an number :) "):
print(num)
x = int(input("Enter a digit: "))
y = int(input("Enter another digit: "))
print("x divided by y is", divide(x / y))
def divide(x:int, y:int):
return x // y
numbers()
Why are you using / there? You separate arguments when calling a function with ,
The reason you're getting that error is that Python is evaluating x / y and passing that value as a single argument.
wild lake
def numbers(num="Please input an number :) "):
print(num)
x = int(input("Enter a digit: "))
y = int(input("Enter another digit: "))
print("x divided by y is", divide(x,y))
print(f"x divided by y is {divide(x,y)}")
def divide(x:int, y:int):
return x // y
numbers()```@arctic arrow How are you learning Python?
arctic arrow
def numbers(num="Please input an number :) "):
print(num)
x = int(input("Enter a digit: "))
y = int(input("Enter another digit: "))
print("x divided by y is", divide(x,y))
def divide(x:int, y:int):
return x // y
numbers()
It does work now
brave oar
fantastic
arctic arrow
<@863255409375707167> How are you learning Python?
Harvard CS50 course
python to be exact
brave oar
Ok, that's cool. Also check that site I mentioned earlier because those resources can help you as well.
arctic arrow
I see I see
Give me a moment, I still don't understand something on this line
def numbers(num="Please input an number :) "):
print(num)
x = int(input("Enter a digit: "))
y = int(input("Enter another digit: "))
print("x divided by y is", divide(x,y))
def divide(x:int, y:int):
return x // y
numbers()
arctic arrow
Is line 3 essentially connected to line 2 or 9?
arctic arrow
Give me a moment, I still don't understand something on this line
```py
def numb...
Cause this seems like line 5 is connected to line 8 just pretending theres lines
This is where I'm confused about
how they are related
brave oar
In the image you just posted you are calling square(x) on line 3.
You are defining the function on line 6
You are assigning the value of calling input("What's x? ")) to x on line 2
and on line 10 you are calling main, which performs those other operations.
arctic arrow
yeah
brave oar
like x or y or z in algebra
arctic arrow
yeah
brave oar
since you square a number by multiplying it by itself it makes sense that square only takes one value.
arctic arrow
yeah
brave oar
Do you understand now?
arctic arrow
So essentially, the
def numbers(num="Please input an number :) "):
print(num)
x = int(input("Enter a digit: "))
y = int(input("Enter another digit: "))
print("x divided by y is", divide(x,y))
def divide(x:int, y:int):
return x // y
numbers()
the print("x is divided by y is", divide(x, y)), the x and y's are connected to the assigned variables on top,
the def divide() however is a function itself that runs itself with two other variables regardless of def numbers() doing of x and y, acting as a clone?
Not sure if my explanation makes sense or not
but how I would see def divide() and the arguments inside it is just a way to act as a clone for the assigned values x and y to function?
wild lake
https://www.youtube.com/watch?v=1OuRhD7FmTA&list=PLzMcBGfZo4-mFu00qxl0a67RhjjZj3jXm&index=12&pp=iAQB just watch this basic function calls and how it is done ...
arctic arrow
https://www.youtube.com/watch?v=1OuRhD7FmTA&list=PLzMcBGfZo4-mFu00qxl0a67RhjjZj3...
Alrighty
cinder gateBOT
Python help channel closed