🔒 Does the logic make sense, along with the syntax for this loop?

[ruby halo]

dropping_indices = []
for index, row in df_2019.iterrows():
    if ((row['color'] == 'green') & (row['volatility'] < 10 * row['mean_return'])) or (row['color'] == 'red') & (row['volatility'] >= 10 * row['mean_return']) :
        dropping_indices.append(index)
        print(row['volatility'])
        print(row['mean_return'])
    else:
        continue

df_2019.drop(dropping_indices, inplace=True)

I'm not sure if it is catching anything, but it is definitely changing my matplotlib scatter plot

[crystal locust]

@ruby halo

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[little swift]

did you mean to use bitwise and? (&)

also else: continue isn't required in this case, because there is no code to skip after that line

[little swift]

I can't determine if you logic is correct unless I know what it is supposed to do

[ruby halo]

i'm trying to figure out syntax...anything to drop those with those conditions

[ruby halo]

This is the full code snippet:

#I've decided my slope is y=10x, which means its starts at (0,0) and stretches all the way to (.6,6). Anything to the 
#right of that is accepted, to the left marked as a 'NO BUY'



dropping_indices = []
for index, row in df_2019.iterrows():
    if ((row['color'] == 'green') & (row['volatility'] < 10 * row['mean_return'])) or (row['color'] == 'red') & (row['volatility'] >= 10 * row['mean_return']) :
        dropping_indices.append(index)
        print(row['volatility'])
        print(row['mean_return'])
    else:
        continue
df_2019.drop(dropping_indices, inplace=True)

plt.title('Scatter Plot for Mean and Volatility')
plt.xlabel('Mean')
plt.ylabel('Standard Deviation')
plt.scatter(df_2019['mean_return'], df_2019['volatility'], c=df_2019['color'])
plt.legend()
plt.grid(True)
plt.show()

[little swift]

so first, & should be and

[ruby halo]

Anything to the left that is green needs to be dropped, everything to the right as red as well

[little swift]

!e print(bin(0b0110 & 0b1101))

[crystal locust]

@little swift :white_check_mark: Your 3.12 eval job has completed with return code 0.

0b100

[ruby halo]

when does one use '&' instead?

[little swift]

& is only working there because True == 1

[little swift]

it is for bitwise and

  0110
& 1101
-------
  0100

take 1 if both are 1 else 0 for each bit

it only works in your case because True == 1

[ruby halo]

OH i see

[little swift]

instead you should use logical and, which is and

same how you did or

there is also bitwise or, |

[little swift]

did you catch this?

else: continue can be omitted

[ruby halo]

I found out it was the logic, along side the fact about '&'! I'll keep that in mind from now on, thanks!

[crystal locust]

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