🔒 The Winners and Their Scores Problem

[fringe jay]

We have 2 inputs. Which is name[] and score[]. How do I make the output which is who the winner with the highest score is and what is the score? The output is like "The winner is Jonathan with score 86", Also, what if the scores owned by 2 or more people so the output is like "The winners are Jonathan, Chris, Melia with scores 86"

What's the problem here is i can sort the number for the biggest number. But I apparently can not connect the relation between name[] array and score[] array. Can anyone help me tho? 🥲

[ember osprey]

@fringe jay

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[fringe jay]

@umbral robin

[umbral robin]

hi so

have you learned for loops yet?

[fringe jay]

Yeah

I learned while loop

That's why the teacher give me this homework

[umbral robin]

so you know how to use for loops?

also why do you need flush=True when you print?

[fringe jay]

For, do, i think it's for the next meeting tho. Today i learned about while only

[umbral robin]

ok

we can do this with while too

we should break down the problem into parts

• get input from user about how many inputs we will receive
• create lists
• get data from user in a while loop, no need to have the x here, we can just use list.append()
• get the item from the scores list which is the largest
• get the name from the scores list with that same index

can you tackle these smaller problems?

[fringe jay]

I'm so sorry but i think no😭

[fringe jay]

I've tried but i'm still didn't get it

[umbral robin]

ok, i could help you with one part

names = []
scores = []

idx = 0
while True:
  name = input("enter name >")
  score = float(input("enter score >"))

  names.append(name)
  scores.append(score)

print(names)
print(scores)

this is how you would get input, right?

[fringe jay]

Right

[umbral robin]

can you write a loop to find the largest element in an array?

x = [12, 5, 1, 5, 6, 0, 1, 200]

find the largest with a while loop

[fringe jay]

y = x[1]
m = 1
while m < 8
m = m+1
if y < x[m]
y = x[m]
print(y)

[umbral robin]

that is a good start!

however i have some tips for you!

the most important is: naming things is crucial in programming

second, you can use len(list) to get the length of it, so we dont overflow

third, you can use

!code

[ember osprey]

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[umbral robin]

also, indexing in most programming languages starts from 0, not 1

largest = x[0]

idx = 0
while idx < len(x):
  if x[idx] > largest:
    largest = x[idx]

  idx += 1

print(largest)

this is already good!!

its a major part done!

we need one more thing, tho

to keep track of the largest element, AND it's index!

!e

x = [12, 5, 1, 5, 6, 0, 1, 200]


largest = x[0]
largest_idx = -1

idx = 0
while idx < len(x):
  if x[idx] > largest:
    largest = x[idx]
    largest_idx = idx

  idx += 1

print(largest)
print(largest_idx)

[ember osprey]

@umbral robin :white_check_mark: Your 3.12 eval job has completed with return code 0.

001 | 200
002 | 7

[umbral robin]

are you following so far?

[fringe jay]

Yeah, trying to understand all of this so far

[umbral robin]

ok!

!e once you understand it, take a look at this:

names = ["clein", "10x", "sani", "lemon"]
scores = [1, 10, 4, 7]

print('names', names)
print('scores', scores)
print('indexes', [0, 1, 2, 3])

[ember osprey]

@umbral robin :white_check_mark: Your 3.12 eval job has completed with return code 0.

001 | names ['clein', '10x', 'sani', 'lemon']
002 | scores [1, 10, 4, 7]
003 | indexes [0, 1, 2, 3]

[umbral robin]

largest score will be 10, largest index will be 1, so if you do names[largest_index] you will get the top one's name

[fringe jay]

Soo we use len command right?

[umbral robin]

yes!

[fringe jay]

Ahhh

[umbral robin]

!e

x = [1, 2, 3]
print(len(x))

[ember osprey]

@umbral robin :white_check_mark: Your 3.12 eval job has completed with return code 0.

3

[fringe jay]

I just found out that this command exists

[umbral robin]

yeap, its a built-in function, there are many

[dense canyon]

...are you in fact meant to write your own sorting algorithm, here? because the straightforward way of doing this is inds = sorted(range(len(names)), key=lambda i:scores[i]), though it takes using the key argument of sorted.

[umbral robin]

sorting?

wait

[umbral robin]

thats too much to expect from someone who hasnt learned for yet imo

[umbral robin]

they only need the ones with the top scores,

oh there can be multiple winners too

[dense canyon]

IMO, so is writing a sorting algorithm, so I don't really see what the intended solution here- ooh, I see

yeah, I totally missed that. only the indices of max scores is indeed much simpler than sorting them all.

[fringe jay]

Yeahh

Same scores but different name

[gentle mural]

Alternatively, combine the score and name into a list of tuples and sort that

[umbral robin]

we are limited to while

[gentle mural]

As in for is banned or the sort and sorted functions are banned?
Cause it doesn't really matter if it's the former

[dense canyon]

the way i'd write a multiple-max is roughly (spoiler for people who want to figure out it themselves)
||

best_indices = []
best_score = -1 # some number that's <= than the highest score. could use scores[0]
i = 0
while i < len(scores): # in reality i'd use a `for i,el in enumerate(scores)` loop
    if scores[i] > best_score: # if we find a higher score, we replace our list of winners
        best_indices = [i]
    elif scores[i] == best_score: # if we find an equal score, we add to it intead
        best_indices.append(i)
    i += 1

||

[ember osprey]

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