#crackheads do math
1 messages · Page 2 of 1
Do you ever just expand triple brackets when you’re bored
They’re piss easy but there’s something satisfying about them
i hate them
don't do school
stay in meth.
Monthly Meth Session
<t:1651347000:f> <t:1651347000:R>
The disrespect
What’s wrong with them
It’s just multiplication
1 am dude
3:30am moment
many skill issues
timezone moment
man's doing meth session at 1 in the morning
ew
Too late bruv
Too late
lol fuckin nerds
meth
@remote jasperonly fair to rename the chats to crackheads doing meth 😤
oi cunts
me need some help
@undone delta
400 million people live in an Asian country.
a) 17/50 is younger than 18 years. How many is it?
b) 10/50 are over 60 years old. How many is it?
c) 23/50 is between 19 - 60 years. How many is it?
how do i solve this
ah
multiply
for a divide 400 million by 50 and then multiply by 17
for b divide 400 million by 50 and then multiply by 10
for c divide 400 million by 50 and then multiply by 23
no?
yes
no clue
try it it's fun
yes its correct danke danke
i do not understand how teacher expect us to be able to do shit like this after like 2 years of not doing this math
well it's esentially 40/5 and then multiplying 17x8, 10x8, 23x8
and not forgetting the 0s
The container ship M / S Alexandra has just left the port of Hamburg with a full load. 1/5 of all containers on the ship contain computers. Of all containers with computers, 1/4 of the containers contain laptops. This means that the ship carries 150 containers with laptops.
a) How many containers of computers does the ship carry?
b) How many containers does the ship carry in total?
how does one figure this out
educate me
ah
let containers containing computers be x
so 1/4 of x is 150
so containers containing coputers is 600
let total containers be y
so 1/5 of y is 600
so total containers is 3k
think of it this way
if there are 100 containers then 100/5 = 20 containers contain computers
of those 20, 20/4 = 5 of them contain laptops
now replace 5 with 150 and work your way in reverse (that means 150 * 4 * 5)
danke
Hold on hd on
Brih i was about to answer but someok e alrwadu did
sllow
@remote jasper SORRY
The skills you need for those questions are very easy
It’s the wording that will confuse you
Well you know how to divide and multiply
Dang
Calculus has been ok so far
chemistry is what gets my brain fried
Even tho, its still math
Difference is thst I have to memorize what to substitute on the compounds and stuff and it makes no sense at all
english
uni?
Senior high
Dyin man
Even the teacher admits that chem is a boring subject
Its gonna be worse in collage
😩
chem is just hell
"Calculus has been ok so far". Oh to be young and full of hope 
Haha
it only goes down from here
Just like the bell curve
It goes up to the Y X=0 axis from the negative x axis then down again near the X axis but it never meets and ends
That message alone costed 50 braincells
It does
what is this
take me back to the good old days
When math was actually about numbers

A-level further mathematics
College maths basically
Something you’ll be introduced to soon 
soon, well im in 12th rn soo,
This year
💀
ez
Vectors 😎
I think 3b1b has an awesome video on stokes theorem
Or khan academy.
Brown people and m a t h s 🥰
by using math
always give priority to multiplication
btw if you're multiplying a whole number with a fraction multiply the whole number with the numerator (the number at the top)
so follow BODMAS
B- Brackett
O-Open
D-Division
M-Multiplication
A-Addition
S-Subtraction
go in this order
i know that order but like whole number multiplying into fraction stuff is confusing
@remote jasper
terms are separated by + and - signs
ah ok
yes
you get 5z = 4z + 8
5z-4z=8
z=8
5z=4z+8 right?
yeah
here 4z is on the right hand side and is positive
you take it to the left hand side and make it negative
4z and 8 add up to make 5z so if you remove 4z from 5z you should get 8
that is what we are doing here
Same
Ikr
give
4 hours ago 
it should've reached your houses
aaaaaaa
i
c
z
u
h
o
h
MoH - Masters of Hardcore
quick mafs
😱
true
Yes big brain
i agree
i mean he ain't wrong
😩 yea why not
its not possible
(2+4)² is 2² + 4² + 2x2x4 which is 36
2² + 4² is 20
there
joke ruined
you're welcome
🤝

kick rocket from thread when
tomorrow 13:62pm
h
nvm i just realised
if you have more than one braincell unlike me you would realise (2+4)² is 6² which is 36
idk why i thought of this but
im dum
me when calcualting math
Same
Ikr
passed my math exam with that
Alo speaking fax here
Ikr
the chad is collecting your questions https://www.reddit.com/r/IAmA/comments/v3e8ye/i_am_changhsu_a_college_math_teacher_who_posts/
I've successfully completed my last Math exam of the year
POG
🫂
aah that feeling
L + intuitive + trivial + obvious + you fakesolved + wrong answer + incorrect small cases + no proof + well known + failed nationals + failed tst + oeis + d0 + the answer is on quora + mind your decisions video + my dog could solve it + you didnt draw the circumcircle + A hunter and an invisible rabbit play a game in the Euclidean plane. + ratio + you used geogebra + 1/7 + you could have trig bashed + it was R+ --> R+ not R --> R + pointwise trap + hook length formula + i have amputated your legs (without anaesthetic) + you misread the question + B-symmetric + this problem was on cf + L part 2 + ratio + cross ratio + just expand + combi + inequality + tony wang has inverted your mother about the orthocentre (without anaesthetic) + combi again + you paid for a copy of egmo + you spilt your chinese noodle soup + you brought in a protractor + pathological solution + you cut yourself with your compass + you drew triangle before circumcircle + you're a simp + cancelled + L part 3 + you leaked imo shortlist + didn’t finish ACPS + skips class + didn’t learn calculus for physics + can’t do complex bash + can’t walk straight + inverts lines to circles through center of a circle with no special properties + can’t identify similar triangles + can’t synth-solve geo + can’t do write-ups properly + always falls short of time + trivial by 665 theorem + 1-liner + combinatorial nullstellensatz + IMO 2020/2 moment + cited theorem wrong + IMO 2021/2 moment + trivial by sharkydevil and queue point + blocked by 30 mohs p1 + trivial by jensen + trivial by jayasharmaramankumarguptareddybavarajugopal's lemma + sobad + trivial by infinite descent + nut + unoriginal + CCCCCC + used lagrange multipliers + GGGGGG + one point deduction for no diagram + walked out early + you got blocked by pigeon + you can't solve 0 mohs problem + L part 4 + skill issue + configuration issue + you thought you solved collatz conjecture + assumed the triangle was acute + L part 5 + no space because discord nitro
Evaluate the line integral where C is the given curve. We're integrating over the curve C, y to the third ds, and C is the curve with parametric equations x = t cubed, y = t. We're going from t = 0 to t = 2. So we're going to integrate over that curve C of y to the third ds. We're going to convert everything into our parameter t in terms of our parameter t. So I'm going to be integrating from t = 0 to t = 2. Those will be my limits of integration. Now y is equal to t, so I'm going to replace y with what it's equal to in terms of t. So I'm going to be integrating the function t to the third. Now ds we're going to write as a square root of dx dt squared + dy dt squared, squared of all that as we said dt. So we're integrating now everything with respect to t. So this is going to be equal to the integral from 0 to 2 of t to the third times the square root of -- see the derivative of x with respect to t is 3 t squared. So we have 3 t squared squared + dy dt; well, that's just 1 squared dt. So we have the integral from 0 to 2 of t to the third times the square root of 9 t to the fourth + 1 dt. So this is a pretty straightforward integration here. We're going to let u be equal to 9 t to the fourth + 1 then du is equal to 36 t to the third dt and so that tells me I can replace a t to the third dt with a du over 36. And so we're going to have the integral then from -- well, new limits of integration. I'm just going to put some squiggly marks there to remind myself that we switched variables. So I'm not going from t = 0 to t = 2. I'm doing things in terms of you right now. But I have a 1 over 36. I'll put that out front, and we're going to have the square root of u. So u to the 1/2, t to the third dt was replaced by du over 36. We got the 36 out front. And so now this is a pretty easy antiderivative in terms of u. It's u to the 3/2 times 2/3. And again, different limits of
integration. We could figure out what they are in terms of u, but I'm going to convert back into t. So we're going to have 1 over 36 times 2/3 times u to the 3/2. Now, u is 9 t to the fourth + 1, that to the 3/2 power. And now we can go ahead and go from original limits of integration 0 to 2. So let's see, when I put a 2 in here, we're going to have -- 1 over 36 times 2/3. That's going to be 1 over 54, isn't it? So we'll have 1 over 54 times -- putting a 2 in, we have 9 times 2 to the fourth. That's 9 times 16, which is 144 + 1, is 145. So we put the 2 in there, we get 145 to the 3/2 minus, putting the 0 in, we get 9 x 0 to the fourth. That's 0. 0 + 1 is 1. So we just get 1 to the 3/2 or 1. So let's see, what's the best way to write this. How about 1 over 54 -- I guess we could leave it like that. We could also write 145 to the 3/2 as 145 times the square root of 145 and then minus 1. And that is that line integral of y to the third ds over the given curve C.
Evaluate the line integral where C is the given curve. We're integrating over the curve C, y to the third ds, and C is the curve with parametric equations x = t cubed, y = t. We're going from t = 0 to t = 2. So we're going to integrate over that curve C of y to the third ds. We're going to convert everything into our parameter t in terms of our parameter t. So I'm going to be integrating from t = 0 to t = 2. Those will be my limits of integration. Now y is equal to t, so I'm going to replace y with what it's equal to in terms of t. So I'm going to be integrating the function t to the third. Now ds we're going to write as a square root of dx dt squared + dy dt squared, squared of all that as we said dt. So we're integrating now everything with respect to t. So this is going to be equal to the integral from 0 to 2 of t to the third times the square root of -- see the derivative of x with respect to t is 3 t squared. So we have 3 t squared squared + dy dt; well, that's just 1 squared dt. So we have the integral from 0 to 2 of t to the third times the square root of 9 t to the fourth + 1 dt. So this is a pretty straightforward integration here. We're going to let u be equal to 9 t to the fourth + 1 then du is equal to 36 t to the third dt and so that tells me I can replace a t to the third dt with a du over 36. And so we're going to have the integral then from -- well, new limits of integration. I'm just going to put some squiggly marks there to remind myself that we switched variables. So I'm not going from t = 0 to t = 2. I'm doing things in terms of you right now. But I have a 1 over 36. I'll put that out front, and we're going to have the square root of u. So u to the 1/2, t to the third dt was replaced by du over 36. We got the 36 out front. And so now this is a pretty easy antiderivative in terms of u. It's u to the 3/2 times 2/3. And again, different limits of monke jam vary depending on the juice a monke can produce.
addendum
i believe you
Lmao
Calculus Rhapsody
By Phil Kirk & Mike Gospel
(Lyrics below)
We've had this little school project of ours here on YouTube for over 10 years!! It's been so lovely seeing all of your nice comments over the years. We've updated this description to show you what we're up to nowadays (we're both adults with jobs now!). You can find us online at the l...
Fibonacci
That's a work of art
Uploaded to YouTube by FreeHugs
Original by @Buttered Side Down



