#Fix 1v1.lol

64 messages · Page 1 of 1 (latest)

river mesa
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Title

dawn gate
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yes'

sleek lion
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I'll try ig

gray cloud
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yes

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+1 reputaion if u do

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i'll give 5 star review

dawn gate
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ill give 7 stars

gray cloud
dawn gate
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51 stars

gray cloud
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52

sleek lion
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53

dawn gate
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53.0000000000000001

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thats worse

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54.1

gray cloud
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who

dawn gate
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lets gooo

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i won

river mesa
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55

dawn gate
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55.1

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I WON

gray cloud
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55.2\

dawn gate
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nooooooooooooooooooooooo

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whyyyyy

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55.3

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haha

gray cloud
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53.4

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ha

dawn gate
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53.5

gray cloud
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100000000000000000000000000000000000000000000000000000000

dawn gate
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beat that

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100000000000000000000000000000000000000000000000000000000.1

gray cloud
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100000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000

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beat that

dawn gate
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haha

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while u were doing that yap thing

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i got a countryball

gray cloud
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bro

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who

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plays

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that

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in

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the

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big

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25

dawn gate
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100 million people

gray cloud
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vro

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sybau

river mesa
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f(x) =x^^^^G64, g(x) =f(f(x)), and t(x) =g(g(g(x))). t(100^100^100^100^^^^^100000)

river mesa
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The number I made is much greater hmthan if you had an entire universe per atom in our universe and counted the atoms of the new universes

gray cloud
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Google ai said thats the number

river mesa
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Google Ai is stupid

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By having the number in t be greater than 1, it is a number so long that if you were to have every human on earth write it out for the rest of their lives, assuming they lived until the heat death of the universe, they wouldn't come to 1% even

dawn gate
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f(x) =x^^^^G64, g(x) =f(f(x)), and t(x) =g(g(g(x))). t(100^100^100^100^^^^^100001) stars

gray cloud
river mesa
# dawn gate i beat u

Technically yes but with numbers that high you kinda have it completely change something with the exponentiation to make any meaningful change

dawn gate
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{f(x) =x^^^^G64, g(x) =f(f(x)), and t(x) =g(g(g(x))). t(100^100^100^100^^^^^100000)} times 2

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there