#Kerbin to Duna Atmospheric Pressure Changes and Trying to Land Using Math

15 messages · Page 1 of 1 (latest)

robust dune
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I want to find out how fast my vehicle will descend on Duna considering it lands on Kerbin at 8.8 m/s. Since I don't know how to use cheats (and don't want to) to teleport there, how fast would my rover descend? Also, how did you find this answer so I can figure it out on my own for other celestial bodies? (note: using only parachutes because I dont feel like having to control a descent vehicle and land it somewhere else, unless absolutely necessary)

frozen dove
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I am not 100% sure about it. But I think the gravitation of Duna is slightly lower than Kerbin. If you look at stuff like the mass you get a hint about this.

So use the same methods as Kerbin and the normal parachutes, I would say.

robust dune
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So it would descend at relatively the same rate as it would on Kerbin?

tribal osprey
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speed on duna = speed on kerbin * (dunna mass / kerbin mass)

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but that doesn't take into account the atmospheric density

frozen dove
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Density is still not really in the game really, i think

magic shore
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It will be falling faster

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It’s atmosphere is like 0.1x as dense as kerbins

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I’ve found that 50m/s descent is pretty standard for duna with parachutes

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So unless you’re using 3 trillion parachutes you’ll likely want to have some kind of propulsion to slow down just before touchdown

frozen dove
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@magic shore Oh ok, thanks

fiery spire
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Around 37.7 m/s if my math is right

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But I agree with suppise, have some small engines to get that final landing burn instead of stacking a bunch more chutes

steep notch
# fiery spire

Could you tell me what number you used for moles when it’s unavailable