quadratic

[sleek sluice]

the third part
i was able to factorise the first root and get a number, but i am not able to get something good from the second root

[distant flower]

<@&1227988399579730072>

Note for OP

+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.

[sleek sluice]

-6x + 20 bach rha hai iska kya kru 💔

[heady talon]

let the roots be equal to y

wait ill write the soln on a notebook

The answer is the same as the original quadratic

oh you meant second root of the third part

💀

mb wait

[sleek sluice]

Anyone???

[restive onyx]

Dekho, you got the first expression as 7 right? Similarly 2nd expression is 7-6(beta)+13=20-6(beta), but real coeffecients ki quadratic ke roots must be conjugate of each other which aint the case here

So question maybe wrong

cuz complex coeffecients aayenge

[sleek sluice]

Real coefficient = conjugate pairs ? How?

[restive onyx]

Quadratic formula se you can figure out.

[sleek sluice]

Conjugate vala case kese apply Kiya yaha pe, vo to jab D ki value pta ho tab hota hai naa?

I only know 2 cases in which we get conjugate pairs -1) D<0
2) D is not perfect square

[sleek sluice]

I learned this method today I can solve problems by this method but don't get why this works?

[sleek sluice]

+solve @restive onyx

+solved @restive onyx

+solved @restive onyx

[heady talon]

yea this also didnt click for me honestly

so what i did was

try to solve it without using this method directly, just think intuively what i would do if i didnt know this method

i was able to solve it but i still didnt get the intuition, havent visited it in a bit cause i didnt want to spend too much time on it

[sleek sluice]

Oh

[sleek sluice]

Yeah it's solvable actually but it becomes a little too messy I think there's a printing error