integration | iTeachChem | Page 1

tawny wagon Dec 27, 2025, 6:11 PM

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applied kings rule once and thoda simplify hua.

but idk how to solve it fully

left heathBOT Dec 27, 2025, 6:12 PM

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tawny wagon Dec 27, 2025, 6:13 PM

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you apply kings/queens (jo bhi name hai) rule once and the sin term cancels out

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e waala bach rha hai

tawny wagon Dec 27, 2025, 9:24 PM

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Ok so this was solved on the basis of periodicity of functions

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But exam mein kaise pata chalega

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Ki aise hoga ye type

naive river Dec 28, 2025, 5:00 AM

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u could also break into intervals which is basically the same as period like [sin(pix)] will be 0 for positive values of sin and -1 for negative ones so it will change between integral -1dx and 0dx so the first integral comes out to be -52 similarly for the second it changes between 1 and e^-1

tawny wagon Dec 28, 2025, 10:12 AM

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Oh alright

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Thanks

winter perch Dec 30, 2025, 5:28 AM

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tawny wagon Oh alright

Bro ticket close kar diya karo 🫠

ebon axle Dec 30, 2025, 11:39 AM

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tawny wagon applied kings rule once and thoda simplify hua. but idk how to solve it fully

Thingy has period of 2. so consider integral over a range of -1 to 1. Now [sin(pi.x)] ka area 'ere is -1 directly (think about graph). and e^(cos(skibidi)) is a standard formula.

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Whenever you have periodic functions you translate problems like these into "What is the area of 1 period of function centered about a value in such a way as to give us convenience.

#integration