#electrochem
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<@&1227988359910260737>
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.
my approach was checking Eo for each option individually
A. Sn2+ at cathode , Cl- at anode .
Eo = -0.14-1.36
B. Eo = -0.14-0.799
C. Eo = -0.14-0.13
D. Eo = 0 - 0.13
all quantities are -ve so ans should be ABCD ?
it isnt abcd @teal bobcat
can we do the ecell thing for electrolysis tho?
Ah okay it says which is cathode which is anode
then it is direct na
Sn2+ is reduced at the cathode (-0.14)
Ag is oxidised at the anode (-0.799)
so a c d incorrect
and apologies for the confusion, should not check doubts when I am out, do baar aadha sawal padha xD
-ve is fine since in electrolysis you provide an external voltage a littel but more than the -ve thingy so the reaction occurs.
the least negative one happens basically.
and you cant tell full cells from the options, take the individual cathode/anode competing ions to figure out what happens. that is better.
ans key says ABD . ie ABD do no occur
yep
does this track?
and neutral medium me dekh lo H+ ka kinetically favourable nahi hota hai hence
If this was single correct, I would mark A