Thermo

[slender ginkgo]

No idea. Any hints

[north wing]

<@&1227987967939838003>

[north wing]

Note for OP

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[slender ginkgo]

33

[west sage]

basically for endo/exothermic process sign of delta H is checked which correspodns to sign of delta Q so basically first form a equation connecting delta Q to volume uing eqn of graph etc, then observe when a function changes its sign, it must be equal to 0, so set q=0 and solve for volume then

[slender ginkgo]

i figured out this im trying to form a eqn in Q as a function of V then ill diffrentiate it

Im having problem writing the internal energy change here

[west sage]

why differentiate

[slender ginkgo]

Work we can write as 1/2 PoVo

[west sage]

u need to observe a sign change in Q

[slender ginkgo]

At the point where it is going to change from Endo to exo it will be a maxima of Q

after that point Q will reduce

[slender ginkgo]

Yeah this is also correct though

[west sage]

hmm i did it by sign change, but u could be right too firstly for the equation

u should write work usign integration from v=0 to random v, not the entire work

[slender ginkgo]

Oh yeah right right

And abt internal energy?

[west sage]

write it like this

since P and V both are variable

[slender ginkgo]

ill try this

[potent fog]

i think it will be an inflection point but yea the dq = 0 part works.

[slender ginkgo]

why inflection? The total heat is going to be decreased only so there must be a maxima at that point

[potent fog]

my b, local maximum it is!

[west sage]

heres the sol btw incase, setting dq/dv directly zero or integrating it to find q and then setting it to 0 is same here ig

[slender ginkgo]

Yup thats same

[west sage]

yess

[slender ginkgo]

+solved @west sage