magnetics 1

[astral cove]

<@&1227987967939838003>

Note for OP

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[cloud raven]

i started by taking an element of thickness dr at distance r from centre
Ienclosed = J(r) * 2pirdr

applying amperes law
surface intergal of B.dl = mu * J(r) *2pirdr

i am stuck here

cant figure out dl vector

and cant take out Bvector out of the integral since its a func of r

or can i ??

[serene fable]

You need to do this

$\oint\vec{B}.\vec{dl} = B(2\pi r)=2\pi cr^{\alpha+1}$

[covert crag]

Real potato

[cloud raven]

this would mean B is constant tho

taking it out of the integral

[serene fable]

and then 2picr^alpha+1 =ux that inetgral of j(r)

And apply newton lebnitz

[serene fable]

It varies with distance

So at a distance r it would be constant right?

[cloud raven]

exactly . constant maanke integral se bahar thodi le sakte

[cloud raven]

oh.

weird

but ok proceed

[serene fable]

Circle pr koi bhi point exactly r distance par hi to hoga bro centre se

Circular loop lia na

Area 2pi r

Samjha?

$2\pi cr^{\alpha+1}$ = u_o\int_{0}^{r}J(r)2\pi rdr$

[cloud raven]

yeah yeah

[serene fable]

Sorry forgot a pi

[cloud raven]

oh so now u differentiate both sides

[serene fable]

Ab isme lebnitz laga de

Ajyega j(r)

[serene fable]

Yup

[covert crag]

Real potato
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[cloud raven]

+solved @serene fable