#Integration 2

1 messages · Page 1 of 1 (latest)

last venture
bleak mesaBOT
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<@&1227988399579730072>

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last venture
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i dont have a doubt in the working of the solution

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i just wanna know what are the hints for such particular substitution ( example 3 and 4)

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like what info does the question contain to make my brain think of 2x+2= 3tantheta

tacit heath
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You're asking for 3 ohh

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I was typing for 4

last venture
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both

tacit heath
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See for 3 I have a good explanation

fierce brook
# last venture

Root k niche perfect square banaya kro sbse phele waha se kuch hint mil jata hai

tacit heath
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You see a square term forming

tacit heath
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Usme when you see a^2+x^2

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To vahan pe you definitely know ki somehow tan or sec involved hoga

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'cause sec^2 = 1 + tan^2

last venture
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why not cot or cosec

tacit heath
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Vo kar lo

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Usse bhi same result aayega

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Not much of a difference

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Whenever you see squares being added inside a square root

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First thought should be trigonometric substitution

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Chahe numerator me ho chahe denominator me

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This works is virtually 90% of the cases

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And 4 me

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You got this one to 4 ka bolun?

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@last venture

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Yaar gayab na hua karo

last venture
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ek min processing

tacit heath
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Okay sorry lol 😭

last venture
tacit heath
last venture
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yeah makes sense now

tacit heath
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Try visualising this in different contexts

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Alag alag situation me

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Almost everywhere
It will make sense

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So 4 now?

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Bataun?

last venture
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yep

tacit heath
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Yeah so usme to andar ka expression hai log ke

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You remember from trigonometry how that relates to Cos2x

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I hope you do remember the relation exactly 'cause I frankly don't

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I just remember it looked something like that

last venture
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cos2x= 2cos^2x-1= 1-2sin^2x

tacit heath
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And agar ln(something) hai

tacit heath
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Log ke andar jo hai vaise hi kuch milega

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Thodi trigo hai heavy

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I gotta pick my pen and paper too I guess lol

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Trig after a long time:)

last venture
tacit heath
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a^2 - b^2

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Identity lagayo

last venture
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matlab?

tacit heath
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Difference of squares yaar

last venture
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we can see that (sinx+cosx)(sinx-cosx)= co2x

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ill try subbing in this

tacit heath
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(Cosx-sinx) buddy

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Not sinx - cosx

last venture
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yeah

tacit heath
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$ \ln \frac {\Bigg \bigg{2 \times \sin{x} \cos{x} \bigg} {\cos{2x}} $

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Chala kyun nahi 😭

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Itni mehnat se likha tha

last venture
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oh my my latex wale bhaiya 🥵

tacit heath
last venture
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bruh just use desmos and snipping tool

tacit heath
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Socha test kar lun

last venture
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works like a charm

tacit heath
last venture
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yeah yeah.

tacit heath
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If I remember or not

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What I studied in the morning 😭

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Ahhmm so isme upar sin2x laga do

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1 + sin2x

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Divided by cos2x

last venture
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GOD DAMN

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BHAI KI MATHS STRONG HAI

tacit heath
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Naah bhai 😭🙏

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Iske aage tan2x ban jayega

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If I remember correctly

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Then that can be converted into sinx and cosx

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In that form only

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Jo ln ke andar di hui hai

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I don't remember how

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But somehow ho jaana chahiye

last venture
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ln(sec2x+tan2x)

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easy derivative

tacit heath
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Ye kahan bana?

last venture
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1+sin2x)/cos2x

tacit heath
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Accha haan

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Ohh shit

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Sorry

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Ban gaya I guess

last venture
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koi na

tacit heath
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That tan2x can be converted though

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The expression given in the module holds a lot of importance I can tell you by the look of it

last venture
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so the crux of this post is tan substitution and simplifying the most complex term first

tacit heath
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But that expression is very important

last venture
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yeahh

tacit heath
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Jisko directly change Kiya hai

last venture
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dude integration is so random

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requires raw iq

tacit heath
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.:)

last venture
jovial kernel
last venture
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soln dekh ke lagta hai " who tfs gonna think that" and when i actually look at it carefully

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its just

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pure logic

tacit heath
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Integration pe hi hai ek chiz pe

tacit heath
tacit heath
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I'm very curious too now

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'cause I vaguely remember it

jovial kernel
# last venture

Okay, actually I think the way to go would be write the everything inside ln as tan(x+pi/4) first. Then the derivative of ln(tan(x+pi/4)) gives 1/cos(2x) ig?

last venture
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Yeah the crux remains solving the ln() term first

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+solved @tacit heath @jovial kernel