#magnetics
1 messages · Page 1 of 1 (latest)
<@&1227987967939838003>
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.
,rotate
Just give me 5 mins im on my way to home
alr
well limits 0 se pi hogi but that doesnt make any diff to the ans
nope
Fir kya hai?
Im getting u sigm r w only
its less than that
k
yep
Let me see tumne kya gadbad kri hai
sin^3 theta aaja cheye
Ek extra sin kaha se aagya
how tyo integrarte cos^2 theta
cos2x = 2cos^2x-1
Ruko dekhra hu
way off
ok
Ye formula konsa lagaya hai tumne?
tumne kaise kara?
ring
Mene to biot savart law se kia
rings
magnetic field on axis of ring
Um
Ye formula lagane se ig kuch plm aara hai
Kuch field ya to Cancle out hora hai jo isse formula me account ni hora
har element ki add hogi imo
dude 2 baar karli
Ek sin theta extra kaha se aara tera
Aayega to sin^3 hi
Me likh k bheju solution?
yehi aa rha...sigma bhul gya... wusigma/8
Isse thodi kuch farq pdega re
exactly
Ho na ho Kuch calculation error hai
dono se same aa rha
Method thek hai
@fossil flower ky ahai ans
mil nhi rha :sib
Rukja fir me likh k bhejta hu check kr lena kaha tumne gadbad kri
ring wala result hi use karna pls
dx = Rdtheta gives me the correct ans instead of Rsintheta(dtheta)=dx
this also removes one sinx
Ha to yehi galat kia na tumne
dx ki value RdQ hi hogi
han
Acha wo x and y ulta lia hai na
nahi
dx is thickness of shell
along the sphere
but meine differentiate karke y axis mein dx le lia
Acha acha
dx wgera lia hi mt kar
theta ke terms me hi likha kr
Confusion badhta hai zyada variable banayega to
2 pi rcostheta * r dtheta hoga na area
horizontal is theta liya
uss ring ka radius will be r cos theta na
uske circumference * thickness will give area
Yup
@dire steppe close kardu?
yep
+solved @spring trench