#field using dipole

1 messages · Page 1 of 1 (latest)

rigid eagle
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can some1 tell me how to get the answer with and without using dipole

fossil owlBOT
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<@&1227987967939838003>

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rigid eagle
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i tried without dipole and using my imagination i was able to figure out net field should be 4*field due to one charge * sinalpha
(alpha mentioned in fig)

tawny vine
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take out the feild from each charge and get a vector sum

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it should give the ans

rigid eagle
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i got pretty much the same ans but was missing 1/root2

rigid eagle
tawny vine
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dipole here will make things more complicated

raven pendant
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$$\frac{pK}{\sqrt{2}x^3}\left(\hat{z}-\hat{y}+\hat{z}+\hat{y}\right)$$

chrome martenBOT
raven pendant
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That's what I got.

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Try simplifying, i might have made a mistake

rigid eagle
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yep this is correct

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how did u get this

raven pendant
rigid eagle
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i couldnt visualise using dipole

raven pendant
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$$-\frac{\vec{p}K}{r^3}$$

chrome martenBOT
raven pendant
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Use those

rigid eagle
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yeah i got that part

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there will be two components of field due to dipole

raven pendant
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The p vectors are opposite to those vectors I just wrote.

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I flipped them in my head and typed it.

raven pendant
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For field that is. Dipole moment is always - to +

rigid eagle
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the dipole in red gives z-y or z+y

raven pendant
rigid eagle
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i am thinking x+z

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wait a min angle between p vector and r vector is 90 so radial component cancels only the other one remains

raven pendant
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They've given the axes already

raven pendant
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@rigid eagle got it?

rigid eagle
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no not really

raven pendant
eternal quail
raven pendant
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Those don't exist

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Mb mb

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Yeah field is always parallel/antiparallel to dipole moment

eternal quail
rigid eagle
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for the marked dipole i am imagining a plane similar to xy plane but tilted 45 degs from y axis inwards

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now angle between p vector and r vector ( from centere of dipole i.e origin to point M) is 0
so field along r vector becomes zero
field perpendicualr to r vector is kp/r^3