#field using dipole
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i tried without dipole and using my imagination i was able to figure out net field should be 4*field due to one charge * sinalpha
(alpha mentioned in fig)
i got pretty much the same ans but was missing 1/root2
it indeed will but that vector sum itself is bothersome
nah it wont be
dipole here will make things more complicated
$$\frac{pK}{\sqrt{2}x^3}\left(\hat{z}-\hat{y}+\hat{z}+\hat{y}\right)$$
Opt
It's along equatorial plane of both dipoles na?
i couldnt visualise using dipole
$$-\frac{\vec{p}K}{r^3}$$
Opt
Yeah, the two fields are along z-y, and z+y (divided by √2 to make them unit vectors)
The p vectors are opposite to those vectors I just wrote.
I flipped them in my head and typed it.
how did u fig out the dirn part
+q to -q
For field that is. Dipole moment is always - to +
the dipole in red gives z-y or z+y
z-y
i am thinking x+z
x-z
wait a min angle between p vector and r vector is 90 so radial component cancels only the other one remains
@rigid eagle got it?
no not really
dipoles would have effects in their axes, not in one perpendicular to them.
Any reason you have taken the axis to be x?
They have effects along axis perpendicular to them as well
wont that get cancelled out here?
Oh you mean the field along perpendicular
Those don't exist
Mb mb
Yeah field is always parallel/antiparallel to dipole moment
haan matlab they are planar, is what i recall