gritty mauve
according to gauss law flux through this random body should be q1/epsilon. q2 has no contribution in the flux since the electric field lines that enter the body also exit it thus flux is zero (source :https://youtu.be/ZR9pNx90YRU?si=QR84K-VpzGPqruSZ&t=3981)
vale sand
if we apply a similar logic to this ques
This is a uniform electric field right? So the flux will be area of projection*Electric field.
Wait I had a visualization for this...
vale sand
according to gauss law flux through this random body should be q1/epsilon. q2 ha...
Draw a line of electric field cutting the shape at two points. Now the area of projection of small areas are proportional to the distance^2 (Because the radius of curvature is from point to that small area), while the electric field is proportional to 1/r^2
This cancels out and hence there is no flux by the outside charge.
The same doesn't occur in uniform electric field.
gritty mauve
Draw a line of electric field cutting the shape at two points. Now the area of p...
is the logic i gave incorrect? and why is it not applicable in the cylinder ques
vale sand
if we apply a similar logic to this ques
We can't apply a similar logic here because of the lack of proportionality to 1/r^2.
vale sand
if we apply a similar logic to this ques
Wait a min I read the question wrong.
gritty mauve
waiting
vale sand
Yeah nvm it should be zero, I'm dumb ๐
vale sand
if we apply a similar logic to this ques
What is the source, if I may ask?
gritty mauve
ig phy galaxy high then
gritty mauve
What is the source, if I may ask?
phy galaxy
vale sand
ig phy galaxy high then
It should have been a half cylinder here.
Otherwise by gauss law there is charge inside which is not the case.
gritty mauve
It should have been a half cylinder here.
yes that makes more sense
btw
can an objects own electric field give it flux
yes ig
vale sand
can an objects own electric field give it flux
"give it flux"?
Charged objects enclised in a gaussian surface do give flux.
gritty mauve
like if theres a charged disc , it has some field lines. can those field lines give it flux
vale sand
like if theres a charged disc , it has some field lines. can those field lines ...
Like a gaussian surface enclosing the disc? Yep.
gritty mauve
Like a gaussian surface enclosing the disc? Yep.
the disc only
acc to me yes
cuz well theres enclosed charge
vale sand
the disc only
Gaussian surfaces are imaginary.
gritty mauve
oh nvm i was thinking smthing else
gritty mauve
It should have been a half cylinder here.
what if we tilt the entire cylinder by angle theta wrt vertical
keeping dirn of E same
vale sand
what if we tilt the entire cylinder by angle theta wrt vertical
If it's a full cylinder again zero.
If its a half cylinder, area of projection * magnitude of E-field
gritty mauve
If it's a full cylinder again zero.
If its a half cylinder, area of projection *...
consider a closed cylinder , and half it
given radius R and height H
vale sand
consider a closed cylinder , and half it
Does this help?
paper bolt
It should have been a half cylinder here.
A half cylinder with no flat face opposing the curved one, to be precise. Needs to be open.
In fact, that's our basis for applying the projection
gritty mauve
Does this help?
what i wanted to know was if we tilt the cylinder how do we consider tha flux through cap of cylinder
gritty mauve
In fact, that's our basis for applying the projection
yeahhh
dense oriole
+solved @paper bolt @vale sand
jagged shuttle