PnC

[spare barn]

How to do the 4th option
i tried doing it the normal way for least and then subtrating the cases where G1 and M1 are together i dont get ans
2B 2G = 120
3G 1B = 50
4G 0B = 5
these are my final ans including if G1 and M1 are not together

[nocturne roost]

<@&1227988399579730072>

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[exotic meadow]

My approach lemme calc that out real quick

Ahh I'm getting 195

[spare barn]

its also not in the option lol

[exotic meadow]

Yeà

Thnng is

Maine baaki 3 ka final answer tak nikalla hai pele

But 4 ka nahi nikala tha

Idk why

Aur ab nikal ni ra

[tawny wharf]

This is case-working ig.

The only part of pnc I dislike.🥴

But yeah, make cases for there being 2 girls, 3 girls and 4 girls

And in each case account for if M1 and G1 are chosen

Which would give 189 ig

k G means "k girls are chosen"

[spare barn]

ye ik this will work

but what is wrong with my apporach

[tawny wharf]

For the first case there would be 150-20=130 cases feasible
For the second one there would be 10*6-6=54 cases feasible

[spare barn]

why?

[tawny wharf]

Consider 6C25C2 the number of ways for chossing members now let one of 'em be G1 and one be B1 then number of ways to choose remaining are 4C1*5C1

[spare barn]

omg i did that and calculated that as 30 i am beyond cooked 💀

[spare barn]

in the 2nd one

wont it be 10x6 -10

why 6?

5c2

= 10

[tawny wharf]

We are taking 3 girls and have already chosen the one boy (B1), so we only need to choose 2 girls, that can be done in 4C2=6 ways in the second case

[spare barn]

oh fuk ye right 4c2

i get it now

+solved @tawny wharf