Doubt in Q27
how is electric heating related to electric potential?
This is from cengage chapter 3
Heating effect is in chapter 6
#Electric potential doubt
mild sable
amber wolf
plain bloom
I'm pretty sure it's a weird way of asking energy change
mild sable
I'm pretty sure it's a weird way of asking energy change
Oh I see
plain bloom
Which makes sense sort of
mild sable
So is it related to self energy somehow then?
Because that's the only thing I can think of related to this
mild sable
I'm pretty sure it's a weird way of asking energy change
Also wouldn't this be assuming that all of the energy is converted to heat
mild sable
q = it
H = i²rt = Vit = Vq
The last time I did this was in grade 10. I mean, heat is taught afterwards and cengage doesn't mix concepts like that. Shouldn't there be another way
plain bloom
Ok, conservation of energy i suppose.
plain bloom
Original energy is going to be partially stored in the spherical capacitor system, and partially lost as heat
That's more apt.
mild sable
Either all the Kinetic and potential is converted to heat (idk how this will be solved,not enough data imo) or maybe the charge expands the shell and the excess energy is converted to heat?
This might be solvable. Might have to derive the formula like self energy tho
mild sable
Original energy is going to be partially stored in the spherical capacitor syste...
I thought that too but then again, capacitors is next chapter so you might be able to solve that but there should be a way to solve using only potential
plain bloom
Well the capacitance is derived from potential, so technically this comes first
mild sable
True
Welp, howd we go about this though
@plain bloom how would I work out the math for this
Can you give me maybe the first 1-2 steps?
plain bloom
Self energy of a shell is Kq²/R iirc
mild sable
KQ^2/2R
plain bloom
Then, charge transfer will occur until potential of both surfaces is equal, so do q1/R1 = q2/R2 as well as charge conservation to figure out charge on each
mild sable
I don't remember the derivation.
dw=Vdq=Kqdq/R
Integrate from 0 to Q