De broglie λ

[gaunt cedar]

What's the mistake in my sol.?

[still tartan]

<@&1227988359910260737>

Note for OP

+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.

[gaunt cedar]

,rotate

[eager kettle]

Ig the energy is equal to h*v/lambda thing is incorrect.

It would be h/mv=lambda_p and then (mv^2/2):hc/(h/mv)=v:2c=c/4:2c=1:8

[ripe tartan]

can u explain why

[vapid rune]

I don't think kinetic energy of electron can be given by h nu

That's something called Compton frequency etc.

Ke is always 1/2 mv2 (for non zero mass things lol]

[scenic kraken]

OMG I CANT READ I SOLVED IT THINKING IT READ PROTON

BRUH

[scenic kraken]

i think you wrote the expression for energy wrong shouldnt it be like K.E electron= h^2/2lambda^2 Me

and photon energy is just hc/lambda

[lyric gull]

For massive (having mass) bodies, kinetic energy is p²/2m
For non massive bodies, ie, quanta/photons, it's pc = h(nu)

[gaunt cedar]

+solved @lyric gull @scenic kraken @eager kettle