#Chemical bonding, dipole moment of attached rings
hoary star
hazy heath
hoary star
I get the concept of partial positives and negatives forming because of resonance
But what does aromaticity have to do with anything
stray cedar
I get the concept of partial positives and negatives forming because of resonanc...
This has a huge dipole moment. Like 7.6 debye iirc
stray cedar
why on earth tho
Charge separation makes it really damn stable.
And it's large enough to facilitate pretty large scale electron displacement.
twin shell
But what does aromaticity have to do with anything
I guess because more the charge difference, more would be the aromatic character?
Since it is already aromatic
ebon jasper
Top 500 right?
sterile nexus
But what does aromaticity have to do with anything
there is increased delocalization of electrons
cursive vault
I get the concept of partial positives and negatives forming because of resonanc...
it technically not partial its complete -ve and +ve which is very stable cause of aromaticity
hoary star
yeah true mb its not a partial charge in the traditional sense
hoary star
there is increased delocalization of electrons
now i don't know why antiaromatic compounds are less stable, but why does aromaticity imply more delocalisation
resonance doesnt care about whether the ring has (4n+2) or 4n pi electrons does it
hoary star
I guess because more the charge difference, more would be the aromatic character...
ah what?
didnt get that
hoary star
Charge separation makes it really damn stable.
could the same thing not be said for (2) and (3)
stray cedar
could the same thing not be said for (2) and (3)
Second one gets an anti-aromatic part so immediately discount it. Third one is in resonance on one side, but not aromatic. Two aromatic rings trumps everything.
stray cedar
we're judging dipole
The others are less likely to have charge separation because that reduces their stability.
hoary star
The others are less likely to have charge separation because that reduces their ...
so if a system is anti aromatic, charge distribution/resonance reduces their stability?
stray cedar
so if a system is anti aromatic, charge distribution/resonance reduces their sta...
Yes. That's why they don't like existing.
hoary star
Yes. That's why they don't like existing.
1st option has no reso shenanigans its just kinda there
2nd option has 1 anti aromatic and 1 aromatic (if we count the middle pi bond as being part of one of the rings in resonance)
3rd option is non aromatic both sides since complete conjugation lacking at the tips
4th option is 1 aromatic and the 2nd also aromatic (counting the middle pi as being part of the right, like they've done in the solution)
verify?
also when one ring is anti and one ring is aromatic, what's the net nature
stray cedar
1st option has no reso shenanigans its just kinda there
2nd option has 1 anti ar...
1st one does have reso shenanigans actually. Double bond is forcing two bonds to be in plane, but the third bond is actually partial out of plane.
hoary star
oh huh
that causes resonance, how?
or did you just mean the double bond is causing weird things to happen
stray cedar
that causes resonance, how?
Remember dancing resonance?
stray cedar
Yeah, so actually I think that's the second highest dipole moment there
hoary star
wow
ill have to look up why aromaticity conditions are a thing
4pi electrons, (4n+2)pi electrons
what it even means to be aromatic and why
regardless, this makes sense now thank u
stray cedar
It's a nice revision of electronic effects lol
hoary star
+solved @stray cedar