fathom dagger
The number of moles of acetic acid here are = 45
number of moles of H2O here are = 150
We use the Kf of water here to get the correct answer because water has more moles
But acetic acid is definitely not negligible here
Suppose we had 99 moles of acetic acid and 100 moles of water. Would we still use the exact Kf of water? why? if there were 101 moles of acetic acid and 100 moles of water, would we suddenly use the Kf of acetic acid? how does this work
compact sundial
The number of moles of acetic acid here are = 45
number of moles of H2O here are...
Acetic acid means glacial acetic acid na? It's not a solvent at all
fathom dagger
Acetic acid means glacial acetic acid na? It's not a solvent at all
oh interesting
wait
how would colligative properties work if the solute was liquid
liquid-liquid solution
compact sundial
Raoult's Law applies I presume there. We haven't defined our colligative properties for liquid-liquid solutions in twelfth I'm pretty sure.
fathom dagger
ah oke
so for solid-liquid
freezing point of the solution = freezing point of solvent
compact sundial
so for solid-liquid
Yeah, we consider a 'non volatile' solute
fathom dagger
yeah
compact sundial
Liquids, though they may be really stable, will still technically volatile to a point.
fathom dagger
ahh okay
compact sundial
Abysmally low vapour pressure is still non-zero
vale jetty