#Probability / sets, plotting P(A' | B') on Venn diagram
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I thought A' | B' is = the outer region (1 - union of A and B)
which yields 5/12, but that's wrong
I thought that cuz if you imagine reducing the subset to B', then A' given B' is just the outer region right
this is the real answer, in which they've divided the answer that I got by P(B')
while it seems obvious that P(A' | B') wont just be P(A' intersection B'), where am i going wrong in the Venn diagram approach?
Venn diagram also gives the same ig
yeah that why'd you divide by 2/3
by P(B') i mean
i thought it was just 5/12 via venn diag
Because it is given P(B') has already occured.
Which means what you consider is the universal set is now basically B'
OH
Which means that probability of all the portion inside the B' get scalled by 3/2
ahhhhhhhhhhh
Because now P(B'|B')=1
Np.
+solved SirLancelotDuLac