#Bond angle

1 messages · Page 1 of 1 (latest)

indigo bolt
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Isn't benzene bulkier than those 2 CH3 grps. to cause more bond angle ?

bitter kernelBOT
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<@&1227988359910260737>

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fervent citrus
indigo bolt
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if benzene is bulkier so y the bond angle is lesser as compared to methoxymethane

indigo bolt
feral ledge
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But don't know the correct reason to explain first one

indigo bolt
real swan
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in phenol, 1 lone pair is in conjugation with the ring

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in methoxymethane, there's 2 unscattered lone pairs

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so i guess lonepair-lonepair repulsion causes the higher angle

indigo bolt
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i took H2O for explaining my pt. if lone lone pair repulsion is greater so the effective bond angle b/w COC should decrease

stoic snow
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Methoxymethane is some ether exception iirc

real swan
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hmm

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yeah this is weird

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shouldn't the LP-LP interaction be greater than BP-BP interaction, reducing the ether angle instead of increasing it

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@fervent citrus thoughts?

fair tide
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i think it's smthing to do with their hybridisation. Like in methoxymethane, o is sp3 and lp strongly repel ch bond so more bond angle. In phenol o is partially sp2 due to reso toh ussey mabe lp repulsion reduces and bond angle becomes closer to tetrahedral

fervent citrus
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Ok, not an amazing explanation on my behalf, and it's sort of unsatisfactory but the only thing I can think of is that in methoxymethane,

the compound exists as a superposition of its hyperconjugated structures right? So, there are net δ- charges on the carbons which are repelling each other, thereby increasing bond angle.

With phenol, resonating structures have no issue like this because on the other side, H doesn't have any electronic effects going on.

indigo bolt