#Nested function expansion
1 messages · Page 1 of 1 (latest)
<@&1227988399579730072>
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.
Given that g(x) is this
i keep getting it wrong so if someone could confirm the method that'd be nice
Well, check the output of g(x) for each of the boundary values of x
g(x) is never negative right?
So f(x) = 2+2g(x) will never apply
g(x) is between 0 and 3 for all values in domain
So it's always going to be definition two of f(x)
given a g(x) condition, i have to check with both parts of the function to see what parts of x satisfy it?