How to go about option (3) and (4)?
#EMI+Mechanics Doubt
lunar scroll
sharp viper
candid narwhal
How to go about option (3) and (4)?
Tf is this question? It looks nice, but it also looks like someone was asked to cram as many topics as possible into one question
lunar scroll
I mean yeah but the doubt was how do you find the energy of the system.
candid narwhal
Just a moment, what's that q/ω?
lunar scroll
Ig the potential difference*effective current would give power but don't see how to find energy and stuff
candid narwhal
I forgot the rotation thing. How do you figure out how much it rotates again?
lunar scroll
I forgot the rotation thing. How do you figure out how much it rotates again?
Amplitude?
candid narwhal
Amplitude?
Mhm
lunar scroll
I mean there are two shms right? So amplitude ke liye we somehow need energy and for energy (I think) we need amplitude.
candid narwhal
No no, I mean the simplest case. There's a charged disk and magnetic field changes.
I forgot that
And I don't have notes for that
lunar scroll
No no, I mean the simplest case. There's a charged disk and magnetic field chang...
That would just give rotation no?
candid narwhal
That would just give rotation no?
Yeah.
How much?
The angular velocity
I just remember i = ωq/2π
How to relate it, I forgot.
lunar scroll
Omega would be qB/m ig
unborn viper
😰
lunar scroll
? Would it?
qvB=mvomega for a particle and then for entire disk omega=qB/m ig,
unborn viper
why is it even rotating
ik that tension hoti hai closed loop mein in a magnetic field
but switching off the magnetic field will just induce an emf?
candid narwhal
I got q²B²R²/4M as the total rotational kinetic energy
lunar scroll
Ah. How?
candid narwhal
0.5Iω²
lunar scroll
Yeah, wait that makes sense.
More like ω= B(dq/dm) i suppose
But this omega is in case of disc rotating under influence of constant field right? While in this case, we are dealing with shm and motion due to changing flux?
candid narwhal
A disk would not rotate because of a constant field in the first place.
It would be an impulse I think
∆ω = (dq/dm) ∆B
lunar scroll
Ah I see.
worldly gate
Yeah, wait that makes sense.
More like ω= B(dq/dm) i suppose
dq/dm ?
Can you explain what it is i don't understand
candid narwhal
Idk either
lunar scroll
Oh right I forgor about this.
lunar scroll
∆ω = (dq/dm) ∆B
This make sense. Rotational energy would be q²B²R²/4M so max P.E. in spring would be the same. But what about max. P.E. in string?
candid narwhal
This make sense. Rotational energy would be q²B²R²/4M so max P.E. in spring woul...
Wouldn't it be half of that energy?
No wait
Nvm
When the string is stretched taut, the spring is at original length
lunar scroll
When the string is stretched taut, the spring is at original length
Oh right.
So neither 3 nor 4 would be correct?