Thermodynamics 2

[slim cobalt]

It's an isothermal process so why can't we use isothermal formula for workdone?

[zenith quest]

<@&1227987967939838003>

Note for OP

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[crisp cobalt]

Phase change is happening

All standard equations apply only to an ideal gas.

[slim cobalt]

So what to do?

[crisp cobalt]

Heat energy sirf latent heat of vaporisation hoga.

Work done will be -p∆V

First law

But don't take my word for it, Thermochem is my weakest topic in Physical chemistry

[slim cobalt]

Alr thanks 👍

[slim cobalt]

This is physics btw

[crisp cobalt]

Oh then yeah, take my word for it

Thermodynamics in Physics is a strong suit of mine.

Don't ask how, it is.

[slim cobalt]

It's just that chemistry sucks man xD

[crisp cobalt]

15/100 in thermochem.

92/100 in physics thermodynamics.

Right it's bedtime. G'night.

Hope you got the question.

If you have anything from org chem, do ask.

Not now, post it.

[slim cobalt]

Aight thanks a lot bro

[slim cobalt]

Gnight

[weary bloom]

check my sessions yo

nighto

[weary bloom]

what is your attempt so far? Opt gave you the right starting point.

two things are happening dE = q + w

both q and w are involved.

q from latent heat. and w from pdV

[upbeat marlin]

Q = U + W laga le

W is P∆V

Q Lf hojaaega ig

[slim cobalt]

This is correct, i was using the isothermal work formula before, nRT ln(v2/v1)

@weary bloom

But that's only for ideal gases

Here water was in liquid state before so we can't use it

Is that right?

[weary bloom]

This is for reversible processes.

[slim cobalt]

Aaahh

Damn i get it now

+solved @weary bloom @crisp cobalt @upbeat marlin