Straight Lines Doubts

[high wraith]

<@&1227988399579730072>

Note for OP

+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.

[grizzled ferry]

Which question?

Also, btw, in case you didn't want to share your info, there's a name visible in the url

[dark prawn]

65/66 and 59/60

[grizzled ferry]

Share image pls

Cropped ig

[dark prawn]

Yeah just a minute.

[dark prawn]

r/croppingishard moment fr

[grizzled ferry]

The 65th one seems rather straightforward

That's one way of doing it

For 65

66 is a bit tougher

I'm getting single solution

Oooohh I think I got the 59th one

@dark prawn forgive the abuse of notation

[twin vine]

same

[grizzled ferry]

Bunch of calculation errors but I got 60th

@dark prawn

[grizzled ferry]

Right, I'll be heading to sleep, so ping if you want to ask something

[dark prawn]

When you equate the perimeters of the triangles shouldn't it be 6-c and 8+c?

[grizzled ferry]

Oh wait yeah, I made that mistake I think.

[dark prawn]

I'm sorry but what does S mean here?

[grizzled ferry]

Circumcentre

H is orthocentre

G is centroid

I treat them as position vectors here, so just the letters

[dark prawn]

Ah I see.

[grizzled ferry]

3G = 2S+H is just the section formula

[dark prawn]

If we do 6+c instead of 6 and the same for 8, we wouldn't get a simple ratio right?

Like it would be in terms of c?

And then we find the relation with this and y=mx+c?

[grizzled ferry]

Yup

I just couldn't get around to it today

I sort of assumed it passes through origin wrongly in the beginning

[restive wren]

+solved @grizzled ferry