AOD

[willow pulsar]

How can know about concavity in a period without actually plotting the graph like in the option C of 4th que

[round verge]

<@&1227988399579730072>

Note for OP

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[floral bridge]

,rotate

[floral bridge]

f(x)=$\frac{1}{x}-\frac{1}{x^{2}}$, f''(x)=$\frac{2}{x^{3}}-\frac{6}{x^{4}}=\frac{2x-6}{x^{4}}$. Now $x^{4}$ is always positive so for x>3, function is concave up.

[worthy mesa]

SirLancelotDuLac

[subtle cosmos]

you can separate it into 1/x and -1/x2

1/x is rectangular hyperbola 1st and 3rd quad

1/x2 is similar but no -ves (quad 1 and 2)

since we subtract 1/x2 you will have 3 and 4 quad (-1/x2)

[floral bridge]

Oh yeah. This works too.

[subtle cosmos]

Oh without plotting the graph?

sorry did not read xD

https://www.desmos.com/calculator

why is the point 3 significat, samjha nahi

[subtle cosmos]

ah and is this the way you do it using calc? interesting ye sab bhool gaya :P

[willow pulsar]

Thanks man i got it

+solved @subtle cosmos @floral bridge