EMI

[lethal thorn]

bhai unless i'm not stupidly wrong, isn't this absurd asf? firstly velocity wouldn't be constant by itself beacause of the force on current carrying rod in B, so, neither velocity, nor emf, not current, not force, none of these will be constant, F= (Bl)^2v/R
that is a fucntion of v (velocity) and then we can substitute F= m* dv/dt
and now integrate kar ke we'll find out the V at the end, and then simply work done= change in KE

yaha par bhai V ko constant maan kar, F constant le kar, Work= F*l kar diya hai simply, but miraculously velocity constant thodi ho jayegi, usko constant rakhne ke liye hame kuch work karna padega, wahi work toh nikalna hai na

[static root]

subject tag kar dijiye :)

[ripe sparrow]

<@&1227987967939838003>

Note for OP

+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.

[lethal thorn]

oops thnx sir

[daring idol]

the force which you have calculated as (BL)^2V/R it is to keep the loop moving in that direction without change in velocity when you check the directions of the forces you will see that the magnetic force is opposite to the force they have given as F.

so here you can tell that velocity is constant.

[lethal thorn]

yes exactly so we have to find the work done by the force we have provided right? (which is not constant wrt time)

[daring idol]

it is constant because we are making velocity constant using it.

[lethal thorn]

got it

thankss
+solved @daring idol

shit idk how to do that

[static root]

+solved @daring idol