laws of motion

[buoyant flax]

how do i find velocity of c

[gleaming veldt]

<@&1227987967939838003>

Note for OP

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[stray ibex]

if m is the masss

yaha par a aur b kya hai

[buoyant flax]

My bad fig nahi dala

[buoyant flax]

Anyone ....?

[cyan totem]

i m getting option a

[cyan totem]

i realised late it was multicorrect soryy😅

maybe taking it T/2 in constraint equation, u might get an ans...not sure!

[buoyant flax]

Sorry but I don't really get what uve done here

[static raptor]

Step 2 : Conclude that string ( 2T ) acts as an opposing force on block b and block a moves up the incline due to ( 3 T ) 
Step 3 : Apply string constraint i.e sum of Tension and (velocity/acceleration)'s dot product should be equal to zero                                                                       - Applying s/c to find velocity of block a :     (-2T) ( 3 ) + 3T( V ) = 0 ; V = 2 m/s
- Applying the same to find acc of block a :      (-2T) ( 6 ) + 3T ( a ) = 0 ; a = 4m/s^2
Step 4 : Checking relative motion 
- Vel of b wrt a = 3-2 = 1 m/s  
- Acc of b wrt a = 6-4 = 2 m/s^2
Step 5 : Calculating Velocity at point C  
( Velocity/acceleration of pulley is the avg of motion of string at ends of it )
- It is evident that string on left of it is going up with velocity the same as block a so 2 m/s and the pulley is going up with velocity the same as block b so 3 m/s. 
      3 = ( V at C + 2 ) / 2 ; V at C = 4 m/s ```

[slow granite]

awesome inputs

[slow granite]

we good?

[buoyant flax]

in step 5 you are talking bout which pulley exactly?

[static raptor]

pulley near block b

[buoyant flax]

+solved @static raptor