#redox reaction

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dawn scaffold
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In redox questions do I first balance normally and then find n factor of each compound/element like this for example?

desert impBOT
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<@&1227988359910260737>

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Note for OP

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<@&1227988359910260737>

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Note for OP

+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.

dawn scaffold
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Uhhhhhh 💀 sorry for 2 pings it told interaction failed

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and i clicked it again and welp

wise hinge
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its ok

stoic ravine
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Notice the oxidation state of Mg changed from 0 to +2 therefore two mole of electrons were transferred per mole of Mg hence the n factor is 2 in case of Mg

west coral
dawn scaffold
dawn scaffold
# west coral

Good evening sir, thank you sir but my q is different, im asking shd I first balance normally that is for eg Mg + O2----> MgO

where i balance it by doing 2Mg + O2 ----> 2MgO

like that shd i normally balance it first and then find n factor? or am I doing something wrong

west coral
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Hi good evening!

west coral
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but if you have a redox reaction it is better to split into ox red halves

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here, doing so overcomplicates a simple setup

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redox here would be
Mg -> Mg 2+

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O2 -> O2-

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then balance out number of atoms, followed by charge

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you could just balance the equation in a fraction of all this :)

west coral
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but just putting a 2 in a couple of places balances this :)

dawn scaffold
west coral
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the 'balancing normally' if you think it is easy to do, go for it. if it seems complicated, go the balancing of half reaction way!

dawn scaffold
dawn scaffold
# west coral

now I get what the problem was, the q has a h2O in it.. ;-; sorry my bad

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it shd have been NO2 + H2O not just H2

dawn scaffold
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no i mean the q shs have Mg + HNO3 ----> NO2+ H20 + Mg(NO3)2

west coral
west coral
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We good?

dawn scaffold
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kinda

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+solved @west coral @stoic ravine @wise hinge