Typing 5 for input but returning Failed why?

[sharp zinc]

add fmt.Printf("%q\n", answer) in CheckAnswer and see what is the output

Also the global here makes little sense, I guess you are begining that fine, just don't go think this is an acceptable usage of global variables 😄

(this is bad because if there are multiple pieces of code using this, they will colide on the global which is really confusing, you should lookup return)

[split wren]

so should i check answer inAskQuestion?

[sharp zinc]

depends, there are multiple ways to do this

that would work

if you don't know about it, lookup return (really 😉)

[split wren]

I almost forgot i tried to check it on AskQuestion but i got failed again

[sharp zinc]

#1087503625988866048 message ?

[split wren]

isn't that?

[sharp zinc]

I don't see fmt.Printf("%q\n", answer) anywhere here

[split wren]

output of it

[sharp zinc]

and ? (you are almost there)

[split wren]

am i getting wrong something?

it should be "5"

[sharp zinc]

What \r\n is ?

[split wren]

i have no idea

i started today 😄

[sharp zinc]

Yeah np

so you look at your code, you have ReadString('\n')

you can also google "golang trailing \r\n" 🙂

[split wren]

uh should i remove it when i get input everytime?

[sharp zinc]

||(this represent the ENTER key in your terminal)||

you can use strings.TrimSpace

[split wren]

ups i got "" 😄

[sharp zinc]

you trimmed the string \r\n

if you remove all whitespace from \r\n you indeed get nothing

what are you trying to do ? 🙂

[split wren]

get just "5"

😄

[sharp zinc]

I don't belive so, if the user gives you 6, do you want to get 5 ?

[split wren]

nah nah

i mean just input

without \r\n

[sharp zinc]

then why are you not triming the input ?

hum hum ^^ ?

it's the input that you want to cleanup, not \r\n

[split wren]

yes

i suck

[sharp zinc]

we have all been there

[split wren]

sheesh

[split wren]

i noticed it here i typed wrong everything there 😄

[sharp zinc]

@split wren to recap.
ReadString('\n') is inclusive, it will give you all data until it find the thing you pass it in, right now you read until \n which is a magic character representing a new line.

5\r\n is really the key sequence 5 + ENTER (you have an extra \r too because you are on windows)
So what you did is passed your string into strings.TrimSpace which will remove all the whitespaces left and right of your data.
This includes the ENTER key.
Which leaves you with just 5 (or whatever was written in).

[split wren]

I totally understand

thank you so much

Also do i have anyway for convert string to int?

[sharp zinc]

• https://pkg.go.dev/strconv#ParseInt
• https://pkg.go.dev/strconv#Atoi

You really want to start checking for errors tho (no _ := ...).

@split wren you can also lookup fmt.Scan and fmt.Scanf

[split wren]

uh okay

also

i want to check it in CheckAnswer()

it is looking like that

now, the output of the fmt.Printf("%q\n", value) is "5\r\n"

all good

i typed that value = strings.TrimSpace("\r\n")

[split wren]

now it is ""

[sharp zinc]

#1087503625988866048 message 🙂