I just wanted to write a code that could say when the three given inputs ( strings ) are same or not. But I am not able to do so. Any help is appreciated.
#Beginner Doubt.
velvet raft
don't do using namespace std
Bad practice and it brings all of the symbols from std:: to global scope which can cause collisions
velvet raft
I just wanted to write a code that could say when the three given inputs ( strin...
line 17:
if (s1 == s2 && s2 == s3)
&& means and
|| means or
velvet raft
Hi
light yoke
don't do `using namespace std`
Bad practice and it brings all of the symbols fr...
I didn't get what you mean by second line but I'll stop doing it from now on
velvet raft
I didn't get what you mean by second line but I'll stop doing it from now on
Things like std::min and std::max become min and max which will collide with other things mamed the same thing
velvet raft
Clangster, I made a calculator using switch
Whoa
light yoke
I got to know if else users do not have good repo..
velvet raft
Perf is basiacltl the same
light yoke
Things like std::min and std::max become min and max which will collide with oth...
Like the mathematic function min(x, y)
velvet raft
Like the mathematic function min(x, y)
Yea
light yoke
Interesting
This reminds me I named a variable abs, which was colliding with mathematic function abs
velvet raft
Yeaaa
velvet raft
Where do I post my calculator
#1204181525336301609
Or wait
#1471800141475217449
@light yoke
light yoke
Yes sir
velvet raft
yellow
velvet raft
Why did the program end when the input was 'j'
if you don't give a valid numbr as input it sets to 0
and 0 > 0 is false so it exited
light yoke
if you don't give a valid numbr as input it sets to 0
How do I avoid this
velvet raft
How do I avoid this
iiii don't know
light yoke
Like I want the loop to work even after someone entered j
light yoke
iiii don't know
Oh well fair..
velvet raft
ive not worked with cin much 😭
light yoke
ive not worked with cin much 😭
Fair fair thank you
zealous wedge
Like I want the loop to work even after someone entered j
Have it receive a string instead of an integer. Then parse the string for a number and respond to non-numbers.
brisk badger
and 0 > 0 is false so it exited
if you feed a char to an int with cin, im pretty sure it just assigns the raw binary to the int, so like im pretty sure a = 32
velvet raft
what the sigma
brisk badger
aparently cin has a .fail property?
std::cin >> value;
if (std::cin.fail()) {
// Handle error: clear flags and ignore buffer
std::cin.clear();
std::cin.ignore(256, '\n');
}```interesting
int value;
if (std::cin >> value) {
// Input succeeded
} else {
// Input failed (wrong type, EOF, etc.)
} ```
undone questBOT
@brisk badger has reached level 12. GG!
light yoke
Okk.... I think I did NOT understand it
tired marten
majority of the times for input you always wanna take it as a string and parse it into the data type you want unless it’s a bool and use an execption that’s how it’s done in a lot of industry
light yoke
majority of the times for input you always wanna take it as a string and parse i...
Yes, that helped me
tired marten
Yes, that helped me
Good
azure shore
Like I want the loop to work even after someone entered j
i mean u could use a if to check if the number was 0 and then tell them to input a valid number
velvet raft
i mean u could use a if to check if the number was 0 and then tell them to input...
what if they give 0
velvet raft
Undefined Behaviour; you have to initialize x before ever reading it
you have
int x; // uninitialized
while (x > 0) /* this is UB as you just read an uninitialized variable */ ...
does c++ support type() function
velvet raft
does c++ support type() function
typeid()
but that uses RTTI
it works most of the time
you should tyr it
azure shore
type() like gives you the type of thingy like if its a function a string or sum
velvet raft
yeaa thats what typeid does in C++
azure shore
yeaa thats what typeid does in C++
ohhhh
then cnat u do
if typeid(variable) == string then repeat
like a what was that loop
velvet raft
what's the type of variable tho
velvet raft
it's gonna be int right
azure shore
I FORGOT
I FORGOT WAHT WAS THE LOOP
that was like
{
}while()
instead of while()
{
}
velvet raft
instead of while()
{
}
nah it was normal
azure shore
```cpp
int x = -1;
while (x > 0) {
bla bla
}
```
no no it was like a while adter the brackets
for like repeating loops
foreadh loops or whatever
velvet raft
no clue what youre getting at
azure shore
no clue what youre getting at
do {
// Code to execute
} while (condition); // Don't forget this semicolon!
THIS LOOP
azure shore
do {
} while(typeid(s1) == "string" or "char")
basically
and since a int isnt a frickin string or number
you can
just put the rest of ur code afterw
w
velvet raft
do {
} while(typeid(s1) == "string" or "char")
but
velvet raft
and since a int isnt a frickin string or number
no
int x;
typeid(x) will always give int
because the variable's type is an int
velvet raft
tmeplates are compile time brudda
velvet raft
auto is also compile time
velvet raft
fix it
solution is to use std::string x; cin >> x
and then parse number
if not number then you handle
azure shore
smart
velvet raft
not my sol
azure shore
but i feel like there should be a simplified way to do ts