sapphire

[wary peak]

@nocturne sierra 记sₙ为数列{an}的前n项和，已知a₁=1,{sₙ/aₙ}是公差为1/3的等差数列．
(1)求{aₙ}的通项公式

[nocturne sierra]

Hi! You can interact with me by using </chat:1089565531339772006>. Use </help:1093335225687347203> to learn more. (In r/ChatGPT, you can only do this in #gpt-4.)

[wary peak]

@worldly bough 记sₙ为数列{an}的前n项和，已知a₁=1,{sₙ/aₙ}是公差为1/3的等差数列．
(1)求{aₙ}的通项公式

@nocturne sierra /chat 记sₙ为数列{an}的前n项和，已知a₁=1,{sₙ/aₙ}是公差为1/3的等差数列．
(1)求{aₙ}的通项公式

[nocturne sierra]

Hi! You can interact with me by using </chat:1089565531339772006>. Use </help:1093335225687347203> to learn more. (In r/ChatGPT, you can only do this in #gpt-4.)

[wary peak]

@nocturne sierra /chat