#what is 9+5

188 messages · Page 1 of 1 (latest)

bronze umbra
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It's gotta be at least 6 right?

ocean gull
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14, but it may be different if you use mods

bronze umbra
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ok thanksKerbalKlueless

wide current
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i think it's 16

ocean gull
limber pollen
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0
I took the derivative of it :/

bronze umbra
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I got -4 my second time Imma check my math

quaint marlin
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That is one hard math question, but I think it is 3.7416573867739413...

limber pollen
last lark
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well, since 9+10 = 21, and 5 is 5 less than 10, that means it equals to 21 minus 5, which the answer is 16

bronze umbra
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I see your logic but I use graphics overhaul so it's probably more

remote juniper
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dude this is rocket science, but rocket math, i think the answer will be revealed on 1st april 69420

keen current
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I think the answer is 14

dreamy echo
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e

ocean gull
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Get logaritmed L+bozo+ratio

bronze umbra
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Got him

sharp forum
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actually im pretty sure its 14!

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wait actually that might be too high

bronze umbra
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Yeah I'm using mods KerbalKlueless

last lark
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well, since i have stock, i realised it might be lower than my original answer, so maybe 15

bronze umbra
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so, so far we know it is between 3.14159265358979 and 15KerbalKlueless

covert bane
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maybe turn kerbin in a overall-mathunit and try to solve this, or the answer can be found somewhere between the stars i guessValThinking

limber pollen
bronze umbra
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so between 2.718281828459 and 15

keen current
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9 + 5 = E

bronze umbra
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I think it's e^e

ocean gull
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Nah it's e^ln(Ï€)+i

bronze umbra
ocean gull
bronze umbra
keen current
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E in hex

ocean gull
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Well it's somewhere between 2.71 and e^(e^ln(π)+(¥+¢^Ω))

limber pollen
bronze umbra
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for simplicity,
Â¥=T

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¢=c

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Ω=o

ocean gull
bronze umbra
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wait how do i adjust the equation to also include x and y?

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so does T,c, or o equal x

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?

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if t = x the 9+15= somewhere between 0 and -infinity

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so 9+15 in negative

sharp forum
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Real

ocean gull
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T in for time which is often on the x axis

bronze umbra
ocean gull
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Exactly

bronze umbra
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so the answer MUST be nagative

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it could be anything tho

cosmic drum
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there are people who actually needs help with the game, then there is That KSP Guy KerbalKlueless

bronze umbra
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i actually need help

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plus we just had a breakthrough

limber pollen
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It is "omniscient"

limber pollen
limber pollen
# limber pollen Ask ChatGTP

What if we took the integral of 9+5?
We'd then grt 9x+5x... we have to then find out what x equals, so if we set a upper and lower bounds of 0 and this equation when set to x, we should get our answer... plus a few other variables.

bronze umbra
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yeah so then we can finaly know what 9+5 is

ocean gull
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After long hours of calculation I may have finally found the answer

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I may need to double check

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But

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It's 14

sharp forum
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Huge if true

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The calculation of a life time

limber pollen
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Ban

limber pollen
ocean gull
sharp forum
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We need the proof

bronze umbra
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proof

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show us your equations

ocean gull
bronze umbra
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that looks fake

ocean gull
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It was actually a lot simpler than I thought

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I was really surprised

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All the variables (¥,¢,e,i) cancelled out

bronze umbra
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no

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because Y=t

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and t=x

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it creates a range of logorithmic curves

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using the equation e^(e^ln(π)+(¥+¢^Ω))

limber pollen
limber pollen
bronze umbra
limber pollen
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.

...

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Buh

bronze umbra
sharp forum
ocean gull
sharp forum
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Dear god

wide current
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what is this black magic

ocean gull
sharp forum
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Not a Texas instruments, might be incorrect

ocean gull
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Il put it in a ti84 in a few hours to be sure

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Alr you couldn't possibly doubt this

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I used TALLY MARKS

wide current
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you know humanity wouldn't get anywhere if we didn't question the facts KerbalKlueless

ocean gull
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True

sharp forum
limber pollen
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This is falsified information

limber pollen
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It's obviously faked, just as faked as the moon landing (jk)

limber pollen
# ocean gull

This was also done at school, has to be fake, just like every news station (actually kinda true, each news station has some amount of truth as well as un-backed claims)

limber pollen
limber pollen
limber pollen
# ocean gull Ok close enough

Not when you're in a space ship, you don't say "close enough"
You overstated the accuracy.
You have false information.
Stop spreading as many lies as politicians on election campaigns

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We should banish you from this thread

ocean gull
last lark
bronze umbra
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gentelmen

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we did it

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the answer is probably 14

sharp forum
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14+- 1

last lark
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i estimate about 14.0002345635756856975967

sharp forum
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round up to 15

bronze umbra
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yeah because thats how that works

sharp forum
ocean gull
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Yay

bronze umbra
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so our final equation:

9+5 ~ 15

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solved

last lark
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✅

wide current
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i disagree

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if you do 9+5 and get 15 you have to add the 2 for ksp 2 KerbalKlueless

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so then it'll be......

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what's 15+2

limber pollen
main fern
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it proves itself

bronze umbra
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Hmmmmm

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can I see a logarithmic graph to prove this

main fern
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my proof is that logarithms suck

bronze umbra
limber pollen
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log(15+2)

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log15+log2

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idk after that

ocean gull
bronze umbra
main fern
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log15+log2 = log^2 + log2 + log15 + (15*2)

ocean gull
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Log5+log2=log(5*2)

main fern
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log = 10*9

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10*9 = 90

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90=9*0=0

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Thus log15+log2 = log^2 + log2 + log15 + (15* 2) = 1* 5 * 2 = 10 = 1*0 = 0

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THUS 9+5 = 0 (plus or minus 0.000000000001i)

bronze umbra
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well is it plus or minus

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(difinataly possible to tell)

main fern
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Both, it has 2.0001 possible answers

bronze umbra
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ik

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im just like to be stupid

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like roleplaying

main fern
vale condor
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its 1 idiots

craggy prairie
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guys

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i have the answer

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its -9

thin sluice
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01

cursive bone
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easy one, 3.1415926535...

spark salmon
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Legend has it, the answer to this question is still unknown to this day…

dire grove
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ITS WINDOW

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🪟

viral fog
cold tide
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It's 14.495978707

main fern
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it's most likely 14

dire umbra
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9+5?
Last time I checked, adding a 5 to the end of a 9 made 95

fresh thorn
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14

main fern
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14