differentiation - inverse trig functions

[midnight palm]

FUCK IM SORRY

i got the error: thing

bruhh two generals so gay

ok it's not cotθ, but rather cscθsecθ

[obtuse valley]

is the answer 0

i tried using arctan a + arctan b = arctan ((A+B)/1-A*B) formula which would give arc tan of infinity as denominator ends up in a zero value

arc tan of infinity is pi/2

[midnight palm]

yeah the answer is 0 but i used a rather weird approach

i assumed x/1+x² as t

arctan(t)+arctan(1/t) is π/2

[obtuse valley]

even i had thought of using tan theta by 2 ka formula but that really wouldnt be working here

[obtuse valley]

yeah

wait

[midnight palm]

diff of π/2 is 0 ofc

[obtuse valley]

yeah right

[obtuse valley]

thats what it is

both ways same thing

[midnight palm]

then another approach was to apply d/dx of arctan x + arctan(1/x)

using chain rule

1/1+x² - 1/1+x²

or 0

[midnight palm]

thanks for the help though

[midnight palm]

ohh yeah lim x → 0 of n/x

[obtuse valley]

thats longer tbh

[midnight palm]

yeahh

[obtuse valley]

arent you in 9th tho

@midnight palm

[midnight palm]

yeah

[midnight palm]

narayana moment

[obtuse valley]

oh god

i pray for u

[midnight palm]

lol