MAM reduces 99% of the pins with crystal

[devout nebula]

What about cases where the pin is required to hold up a shape above? Or are you assuming that a crystal pass will be done every level?

[glad lantern]

All pins that need to be crystal are removed. no pin is needed to create crystal if you already have a piece. except the forms that have 4 pins, you need at least 1 pin

[devout nebula]

I understand that. But that's only true if the pieces will not fall down to the lower level. Which means you must be crystallising after each level, and not saving fluid if there are two crystals of the same colour in a row?

[glad lantern]

To make crystal forms it is necessary to do it plant by plant. Well, if it is not done this way, the glass will break. You have to assemble the crystallized piece if it has glass and assemble the 2nd floor without glass. Go back to step 1 until creating the last floor.

A glass factory has 4 assembly plants and 4 intercalated crystallization plants m = assembly c = glass. mcmcmcmc

and I understand about saving ink. But I tell you that with a single ink pipe I am supplying 6 factories: 3 with glass + 3 without glass. I don't know why save ink, honestly.

[devout nebula]

If you have two red crystals in a row, you can skip the first crystal pass and only do the second one, as long as your shape doesn't fall. This ROS1 shape, for example, can be done with only one pass, as long as your MAM knows that the shapes won't fall.

[devout nebula]

"Because it's fun". Basically. But it does cost more in pins. 🙂

[glad lantern]

There is no problem using pin reduction. You can use it if you have control over the same glass color between several plants in a row.

[devout nebula]

I was trying to find a way to do what you are doing and what I am doing at the same time, and it's hard. I think I can get away with:
If a layer is doing a crystal pass, use gaps instead of pins (or all pins).
If a layer is not doing a crystal pass, for each crystal, look at the layer above: if it has a gap, you can leave a gap. If it has a pin, you need a pin. If it has a solid, check the two adjacent shapes, and if either of them is solid, you can leave a gap. If neither of them is solid, you must have a pin.

[devout nebula]

Not quite: Look at the shape I posted. If you leave gaps, you're fine until the third layer. There, if you use 4 pins, you're good, or a single pin in either of the top corners, but if you use a pin in either of the bottom two corners, it will fall and you will not get your crystal layer.

If you crystallise every level, no problem.
If you use fill pins for full-crystal levels, no problem.

[glad lantern]

Send me that form. I'm going to see if my MAM can do it with the reducer.

[devout nebula]

I believe it would be: {SuccSucc:SuccccRu:cccccccc:RuccccRu:CuccccCu}

[devout nebula]

It was one I got a week ago as an ROS in Insane.

[glad lantern]

leI will remove the last plant. I only work 4 floors

[devout nebula]

If your MAM puts the pin in either top corner, or if it crystallises after each layer, it will work.

{{SuccSucc:SuccccRu:cccccccc:RuccccRu}

[devout nebula]

Same issue. 🙂

I was trying the same kind of pin reducer you are doing, and I found some edge cases mine did not handle well if I tried to also reduce the number of crystal passes.

[glad lantern]

that way only need 1 pin for the plant which has 4 pin

[devout nebula]

Yes. As long as the one pin is in the right place, or as long as you run crystals every level. If you try to save on fluid, then {cccccccc:Rucccccc:ccRucccc:ccccRucc} will also be a problem for gaps-not-pins. But it will work if you crystallise every level each time.

[devout nebula]

And, there's no reason to save on fluid, except that you can and it's fun to build. Like saving on pins.

[devout nebula]

Yes, because either you are crystallising after every level, or you put the solo pin in one of the top two corners. Either of those will work.

It's only if you don't crystallise every level that your method will break.

So saving on fluid means not saving as much on pins.

[glad lantern]

I crystallize after each assembly

The problem is powering 6 factories with pin and I can only use the 3rd floor with pin, the other two are busy with material. Give me a second and I'll give you an image. This way you will understand why I save on pins and not on ink

powering 6 factories with a single pin phase is impossible

[devout nebula]

That makes perfect sense.

I feed a full notch of every shape, including pins. I save on crystals just because I can.

[devout nebula]

Then your MAM will never have a problem using just one pin for a whole crystal layer, and no pins anywhere else that doesn't ask for a pin specifically.

[glad lantern]

Well, in the last piece I make I need 6 pins, with the reduction only 1