timmy_error

[vale shore]

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[hallow granite]

Hi! Can you share the request ID (req_xxx)? Here's how you can find it: https://support.stripe.com/questions/finding-the-id-for-an-api-request

[pallid mist]

Sorry, I can't find this request ID. Here the response received from Stripe Create Payment Intent API is
{"message":"This object cannot be accessed right now because another API request or Stripe process is currently accessing it. If you see this error intermittently, retry the request. If you see this error frequently and are making multiple concurrent requests to a single object, make your requests serially or at a lower rate.","type":"invalid_request_error","code":"lock_timeout"}

[hallow granite]

Or do you have the PaymentIntent ID?

Or can you share with me your merchant ID? you can find it from the Stripe Dashboard -> Settings ->Account Details

[pallid mist]

acct_1EBdKlB02sbMzSSP merchant ID

[hallow granite]

Do you know when this error occured?

[pallid mist]

2024-09-23 04:41:18 UTC+0

[hallow granite]

Ok, found the request, let me take a look

[pallid mist]

OK! Thanks

[haughty horizon]

Why do you need to charge the customer many times?
What's the use case?

[pallid mist]

We provide the partner the service saving the card in advance and charge directly later. And the partner may charge many times in a short time. Is the use case not permitted?

[haughty horizon]

many times in a short time
How many, and in how short time?

Approximately.
But I also don't think that you can charge the customer while another charge is in progress.

[pallid mist]

At most, 2-3 requests can be made in a minute.

[haughty horizon]

Yeah, this might cause a problem. If it's the same customer, why wouldn't you charge them once for the total of their purchases?

[pallid mist]

I'm not sure the partner operates in actually. But from our Log Dashboard, I found many requests were made in a short time.

So, we should avoid the new charging request before the previous one finishes ?

[haughty horizon]

Yes, if it's the same customer.