#probability proof

6 messages · Page 1 of 1 (latest)

open gale
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try find

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P(A' n B')

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in terms of A and B

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so
P(A' n B') is the same as P((A u B)')

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use the addition formulae for P(A UB) so 1- that, and the fact that P(A n B) = P(A) * P(B)

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then from there manipulate it to show
P(A' n B') = P(A') * P(B')
so like u might have to factorise smth out