#Further vectors
40 messages · Page 1 of 1 (latest)
You should have 8z from 2 lots of equation 1
But
I don’t think this works for finding the equation of the plane
You should probably just use vector product on AB and AC to find the normal to the plane and then use the form r.n = a.n and expand it out
Ph yes ur right
Ohh I see
Thank you
We haven’t covered this part of the unit yet but what is r.n and a.n
Like what is r, a and n
Well assuming n is normal
So r is a general point on the plane so (x,y,z), n is the normal vector
And a is any position on the plane
So that could be A,B or C
I see thanks so much
Using the vector product method is just easier imo the other algebra is pretty tedious as far as I can remember
Is that when u form a 3x3 matrix of top row ijk then find the determinant
Yeah
Oh okay thanks, how would I do this thoughr, would my 2nd and 3rd row just be any of ABC?
So you know that any two vectors linking 2 of the 3 points together will span the plane
Well I should say non collinear but it doesn’t really make sense if they are ig
So their vector product produces a vector that’s normal to the plane
So you want to choose any 2 of AB, BC, AC
Thank you so much I’ll try this and I’ll let yk how I get on 👍
I got a and b wrong but c is right
For a it should be x+y=2
And for b it should just be (1,1,0) which the mark scheme has as the normal vector
Why did you dot (-2,2,-2) with (1,-1,4)
You have the normal vector (-10,-10,0) so
-10x -10y = (3,-1,4) dot (-10,-10,0) so
-10x -10y = -30 +10
-10x -10y = -20 or x+y=2
for b you can have multiple answers btw
Since it can be any multiple of (1,1,0)
I thought that’s how u find d with the other 2 (b.c) but now I’m realising cos u explained I should’ve dot r.n
Thank you
But I’m confused isn’t 1,1,0 just the direction vector, would u have to let lambda = 1 for instance then do
r=a + lambdaB
1,1,0 is a vector normal to the surface of the plane
So is 2,2,0
Or any multiple of that vector since all you’re doing is changing the length of said vector
Its direction is constant
Ohh okay thank you so much