#prove shaded area
43 messages · Page 1 of 1 (latest)
ill say what I did:
I took x out of the cubic
x(2x^2 -17x +20)
completed the square and got 2(x-17/4)^2 + 31/16
turning point: (17/4, 31/16)
I think I did it right, so we take the x coordiante of k which is 17/4
and integrate between 0 and 17/4,
is that right? what ive said
I checked mark scheme and it says u gotta differnetiate as well, idk y
<@&791435371564892232>
pls read from line 1, tell me where ive went wrong, or have done something thats not needed
subbed in 17/4 for x and got 89.37...
we want 256/3 or 85.33333333
differenate and equal to 0 then solve for x right
then integrate between the value of x and o
since its minimum turning ponit
dy/dx = 0
if im right
so whenever theres min point u gotta differentite?
yeah if im right
im not 100% sure lemme try this q rq
@brave cosmos
i got ther x coordinate to be 4
x=4 or x=5/3
yeah you got the x coordinate wrong
everything else is correct
i got 256/3
@brave cosmos lmk if yu get it
ah
so u cant complete square to get min point
maybe that only applies for quadratics
<@&791435371564892232>
some1 pls confirm if what ive said is right
completing the square is only for quadratics
alr yeah
you get a min point or a max point which depends on the orientation of the curve
differentiate
swr in yr 12 math whenever yu see the word curve theres atleast 1 q wheere yu will have to differentiate ðŸ˜
wouldnt you just find the derivative - giving you 6x^2+34x+40, then solve for x. then find 2nd derivative --> 12x-34, sub in the values of x to determine which one is the minimum (k) and go from there