#prove shaded area

43 messages · Page 1 of 1 (latest)

brave cosmos
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kinda stuck

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ill say what I did:

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I took x out of the cubic

x(2x^2 -17x +20)

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completed the square and got 2(x-17/4)^2 + 31/16

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turning point: (17/4, 31/16)

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I think I did it right, so we take the x coordiante of k which is 17/4

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and integrate between 0 and 17/4,
is that right? what ive said

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I checked mark scheme and it says u gotta differnetiate as well, idk y

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<@&791435371564892232>

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pls read from line 1, tell me where ive went wrong, or have done something thats not needed

brave cosmos
# brave cosmos

subbed in 17/4 for x and got 89.37...
we want 256/3 or 85.33333333

willow saddle
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differenate and equal to 0 then solve for x right

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then integrate between the value of x and o

willow saddle
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dy/dx = 0

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if im right

brave cosmos
willow saddle
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yeah if im right

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im not 100% sure lemme try this q rq

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@brave cosmos

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i got ther x coordinate to be 4

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x=4 or x=5/3

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yeah you got the x coordinate wrong

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everything else is correct

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i got 256/3

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@brave cosmos lmk if yu get it

brave cosmos
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so u cant complete square to get min point

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maybe that only applies for quadratics

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<@&791435371564892232>

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some1 pls confirm if what ive said is right

astral prism
brave cosmos
astral prism
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you get a min point or a max point which depends on the orientation of the curve

brave cosmos
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so factorising a cubic is useless

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if u wana get min point

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cuz u cant

random imp
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differentiate

willow saddle
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swr in yr 12 math whenever yu see the word curve theres atleast 1 q wheere yu will have to differentiate 😭

ocean flame
# brave cosmos kinda stuck

wouldnt you just find the derivative - giving you 6x^2+34x+40, then solve for x. then find 2nd derivative --> 12x-34, sub in the values of x to determine which one is the minimum (k) and go from there

wicked sky
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you probably wouldn't have to check your answer because its graphed for you

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you can tell which one is a minimum and maximum