#How to do Part b
11 messages · Page 1 of 1 (latest)
Where did you get to
I got the second derivative then tried simplifying it to get some values but it ain't right
I dont think I used e and ln right idk
did you get to e^4x > 3 atleast
that's probably why its not right
f
e^2x - 3e^-2x > 0
e^4x - 3 > 0
e^4x > 3
x > ln(3)/4
f'(x) = 2xe^2x + 6e^-2x
f''(x) = 4e^2x - 12e^-2x
4e^2x - 12e^-2x > 0
4e^4x - 12 > 0
4e^4x > 12
e^4x > 3
x > ln(3)/4
Thank you
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