#Integration by sub
4 messages · Page 1 of 1 (latest)
Which part
Part a
just do what you normally do for substitution
x^1/2 = a^1/2 * sin(theta)
dx/dtheta = 2asin(theta)cos(theta)
a-x = a(1-sin^2(theta) = acos^2(theta)
just simplify everything
4 messages · Page 1 of 1 (latest)
Can someone explain this pls
Which part
Part a
just do what you normally do for substitution
x^1/2 = a^1/2 * sin(theta)
dx/dtheta = 2asin(theta)cos(theta)
a-x = a(1-sin^2(theta) = acos^2(theta)
just simplify everything