#Inclined planes
14 messages · Page 1 of 1 (latest)
is it 0.5g
resolve it
the horizontal force
the particle is going down the plane
so for the resultant force ur interested in all forces which are parallel to the slope
taking upwards as positive, the parallel forces are +30cos30 and -5gsin30
so F = 30cos30 - 5gsin30 = 5a
i was gonna say this as well