#Proof by Induction
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so base case: f(1) = 81-16=65
Assume true for f(k)
now consider f(k+1)-f(k) = 3^(2k+6) - 2^(2k+2) - 3^(2k+4) + 2^2k
= 3^(2k+4) (3^2 - 1) + 2^2k (1 - 2^2)
= 8 * 3^(2k+4) - 3 * 2^2k
= 5 * 3^(2k+4) + 3(3^(2k+4) - 2^2k)
= 5 * 3^(2k+4) + 3f(k)
now as 5 divides f(k)
5 divides 5 * 3^(2k+4) + 3f(k)
so 5 divides f(k+1) - f(k)
so 5 divides f(k+1)