#straight line

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grand barn
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Question 6 please

hushed swanBOT
orchid onyx
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@grand barn did u try subbing the values into the eq

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p=5(2)+1

abstract lotus
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To get the Q coordinate, it's a bit more complicated however follows a similar method.

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In this case, both "positions" have a 'q' in them. Therefore to solve for the q, you put it back into the equation for the line.

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So (3q-2) = 5(q+1) + 1 and then solve for q.

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For the second part, it's just pythagoras