indices

[acoustic tundra]

I’m up to right now 2^x+2y = 1/2root2

[hoary silo]

,w 1/(2sqrt(2))

stupid fucking bot

[grizzled basin]

2^x × (2^2)^y = root2/4
2^x × 2^2y = 1/4(2^1/2)

then equate it all

[hoary silo]

1/2root2= 2^-3/2

[shut whale]

yh i did that

[hoary silo]

2^x * 2^2y = 2^-3/2

[shut whale]

ill show my working

[hoary silo]

x+2y=-3/2

y=-3/2 - x all ova 2

[shut whale]

u mean -3/2

[hoary silo]

what

[shut whale]

oh mb i think im going blind

[hoary silo]

errr i said -3/2

[shut whale]

i didnt see the -

lmao

mb

[hoary silo]

@acoustic tundra dont disappear after askin

[acoustic tundra]

No I’m not I’m reading it tryna understand bro

[shut whale]

should i send a ss of my working out

instead of texts

[acoustic tundra]

I only understand up to 2^x + 2^2y = root2/4

[acoustic tundra]

Would help maybe

[hoary silo]

its * not +

[acoustic tundra]

Oh ye mb

[hoary silo]

convert root2/4 to 2^smt

[shut whale]

check ur dms

[acoustic tundra]

Okk

[hoary silo]

y this dude gatekeeping solution

[shut whale]

u said the solution

[hoary silo]

root2/4
2^1/2 / 2^2 subtract powers
2^-3/2

[acoustic tundra]

Ok I get that now

[hoary silo]

k

2^x * 2^2y=2^-3/2

[acoustic tundra]

Yes so x+2y = -3/2

[hoary silo]

yh

[acoustic tundra]

And then rearrange for y and get rid of the fraction thanks everyone 🙏🙏

[hoary silo]

errr not get rid of the fraction

[grizzled basin]

separate fraction if u want

jus not get rid

[acoustic tundra]

I meant separate 🤦‍♂️

Mb

[hoary silo]

u can if u want

[shut whale]

i only do that with vectors icl