forces

[tight kestrel]

is the answer 0.392

[idle briar]

Why’s your diagram like flipped 😭

I thought it was this

[minor condor]

R always acts perpendicular to the surface

[woven crow]

Everything except R is correct also the component forces should be perpendicular to each other too(u might have meant to do that but it doesn't look that )

[idle briar]

wdym my r isnt right?

wdym by the second part too 😭

[zinc kiln]

yeah your r isn’t correct

and my diagram is the same as yours i just moved the force

[idle briar]

wdym?

[languid quail]

can u show how the force of 8n acting on P would look like when u split up the components without moving it?

[fossil jolt]

Can I have the ms pls

[languid quail]

Why is the angle 40 shouldn’t it be 30

[real cliff]

No, but which one

[languid quail]

We’re the 8n force is

Nvm

…..

I can’t read

[mortal anchor]

i got 0.392

is that right?

[idle briar]

yeah

[idle briar]

for the 8sin40 how do you know if it’s going downward or upwards??

[mortal anchor]

if the force of 8N arrow is pointing diagonally bottom right

[idle briar]

wdym?

[mortal anchor]

think of it like a journey, starting from the end of the arrow without the triangle point

in order to reach where the arrow is going

u have to draw 2 lines to get there

shall i draw it out to make more sense?

[idle briar]

yes pls

[mortal anchor]

lmk if it doesnt make sense

but this is how i understand it

[idle briar]

ohhhhhh omggg this makes sm sense 😭😭

[mortal anchor]

u get it now ?

[idle briar]

i was so confused everytime i drew those forces

[mortal anchor]

yeahhh me too

[idle briar]

tysm

[idle briar]

yeahh

[mortal anchor]

no problem

[idle briar]

so for the 0.5gsin.. would it be pushing to the right?

[mortal anchor]

to the left

shall i draw that out

idm

[idle briar]

yeah pls

[mortal anchor]

cos it's important u get this cos it's usually worth a lot of marks

ok ill do it now 1 sec

[idle briar]

yeahh fr if you don’t get it right the answer is completely wrong

[mortal anchor]

acc do u want me to draw out whole thing

[idle briar]

sure that might be better 😭

[mortal anchor]

calm give me 1 min

Sorry if it’s messy

Ignore top part

[idle briar]

oh right so its different for the 0.5g forces

[mortal anchor]

wdym different

same thing, arrow going down so u do 2 diff arrows that go towards it

[idle briar]

for the 8n forces you start from there, but for the 0.5 forces you start at the beginning and reach 0.5

if that makes sense

[fossil jolt]

draw the arrows

it acting into the angled plane so force would have to go down and another force would up

[idle briar]

wdym by another force would up?

[fossil jolt]

i said down

[mortal anchor]

if it helps, u draw ur R (reaction) force on the particle first (it's perpendicular to the plane) and then u draw a line going straight down from that R force in the same direction but downwards, then try and perpendicularly connect that to ur arrow going down (0.5g)

[fossil jolt]

the force would be travelling down would be add together with the weight for the Normal reaction

[idle briar]

ohh

[idle briar]

lets say the 8n was coming out of the particle rather than pushing in? would the force diagram stay the same

[fossil jolt]

no

[mortal anchor]

if it 8N was going out then the sin and cos forces under the arrow go the opposite direction

so sin would go up, cos would go left

[idle briar]

hm okay

i think i just need to memorise this

[mortal anchor]

no not really

just remember like it's a journey

[mortal anchor]

the cos and sin want to go the long way around using vertical and horizontal lines to go in the same direction as the arrow

[idle briar]

do u mind drawing it 😅

[mortal anchor]

😭 ok

[mortal anchor]

@idle briar do you get it?

[idle briar]

yeahh thanks