#finding expected value using integration

20 messages · Page 1 of 1 (latest)

forest badge
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Can someone explain the solution to part c

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I don't get how to solve it by integration

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umbral fog
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Then just applying linearity of expectation for this specific question

forest badge
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The only thing I know is the E(X)=∫xf(x)

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Can you please tell me how to get to the answer step by step

umbral fog
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Into 2E(H^2) + 3E(G) + 3

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First term was worked out from using the data given on variance and the second term is the one calculated by integrating

forest badge
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I thought we could only do something like E(3x)=3E(x)

umbral fog
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That’s linearity

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Just be aware E(XY) doesn’t equal E(X)E(Y) unless X and Y are independent

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Which is why the E(H^2) part can’t be reduced to simply E(H)^2

forest badge
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Got it👍