stuck on iii) of co-efficient of friction Q

[steady gulch]

so confused! ive got part 2 correct and the answer for that is:
T = 40/(cosα + 0.4sinα)
assuming all i need to do for iii) is find minimum tension and use that to find α
but how do i find the minimum tension? 🫠

[steady gulch]

@heady rampart

[heady rampart]

Not at my desk

I’ll try

Oh

@steady gulch

U just want the biggest denominator to ur expression

[steady gulch]

wait wym

[heady rampart]

Cus

U want minimum T

That’s when the denominator is the biggest it can be

[steady gulch]

yea so u maximise cos alpha + 0.4 sin alpha

how do i do that

[heady rampart]

Yh

Pretty sure it’s gonna be 1

Lemme check that theory tho

[steady gulch]

wait why 1

[heady rampart]

It’s not

Gimme a second

Yo

@steady gulch

[steady gulch]

hihi

[heady rampart]

Yh for past ic

What was it

Part ic

[steady gulch]

part iii)

[heady rampart]

Wait

U want min tension?

I think I got it my bad I’m tripping

[steady gulch]

yus minimum tension

[heady rampart]

Is it

37.1

Ish

[steady gulch]

naw thats what i got tooooo i think

answer is 21.8 deg

[heady rampart]

Oh

Angle

Not tensions

Yh so that gives tension of 37.1

Yh that’s calm them

There’s many angles it could be though no?

Graph is just a transformed sin curve

[steady gulch]

i guess u have to find the one between 0 and 90

[heady rampart]

Cus what I did was just

Math

U need help?

[steady gulch]

ill try again but yea i probs will

1 sec tho let me retry the Q

[heady rampart]

Clm I’m busy rn I’ll try help in a bit

[steady gulch]

okay thank u !